QuestionThermodynamics / Carnot cycle
The maximum efficiency of a Carnot engine operating between 100˚C to 200˚C will be:
- (a) 21.85 %
- (b) 21.14 %
- (c) 22.14 %
- (d) 20.14%
Answer: (b) 21.14 %
η = (Th − Tc)/Th with kelvin temperatures: (473 − 373)/473 = 0.2114 = 21.14% → (b). Trap: using °C (100/200) gives 50%.