QuestionSolutions / van 't Hoff factor
What will be the degree of dissociation of 0.1 (M) Ba(NO₃)₂ solution, if van’t Hoff factor of the solution is 2.74?
- (a) 91.3 %
- (b) 87 %
- (c) 100%
- (d) 74%
Answer: (b) 87 %
Ba(NO₃)₂ → Ba²⁺ + 2NO₃⁻, n = 3. i = 1 + (n − 1)α → 2.74 = 1 + 2α → α = 0.87 = 87% → (b).