QuestionSolutions / Raoult's law
At 298 K, the total vapour pressure in Torr for a mixture of volatile components A and B is given by P = 120 – 75\(\chi_B\) (\(\chi_B\) is the mole fraction of B). What is the vapour pressure of pure A and B (in Torr) respectively?
- (a) 120 and 75
- (b) 120 and 195
- (c) 120 and 45
- (d) 75 and 45
Answer: (c) 120 and 45
P = PA° + (PB° − PA°)χB. Compare with P = 120 − 75χB: PA° = 120 Torr; PB° − 120 = −75 → PB° = 45 Torr → (c).