A 1% aqueous solution (mass by volume) of a certain substance is isotonic with a 3% solution of glucose (Molar mass = 180 g mol⁻¹) at a given temperature. The molar mass of the sub

Question

A 1% aqueous solution (mass by volume) of a certain substance is isotonic with a 3% solution of glucose (Molar mass = 180 g mol⁻¹) at a given temperature. The molar mass of the substance (in kg mol⁻¹) will be:

Vimal Swarnkar · Accepted Answer

(d) 0.06. Isotonic → equal molar concentrations (non-electrolytes). 1 g/100 mL ÷ M = 3 g/100 mL ÷ 180 → M = 60 g mol⁻¹ = 0.06 kg mol⁻¹ → (d). Trap: answer asked in kg mol⁻¹.

Answer

(a) 0.60

Answer

(b) 180

Answer

(c) 0.18

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