0.05 molal aqueous solution of K₄[Fe(CN)₆] freezes at –0.26˚C. Its degree of dissociation will be: (kf =1.86˚C Kg mol⁻¹)

Question

Vimal Swarnkar · Accepted Answer

(c) 44.9 %. ΔTf = i Kf m → i = 0.26/(1.86 × 0.05) = 2.796. K₄[Fe(CN)₆] → 4K⁺ + [Fe(CN)₆]⁴⁻, n = 5. α = (i − 1)/(n − 1) = 1.796/4 = 0.449 = 44.9% → (c).

Answer

(a) 48.2 %

Answer

(b) 54.9 %

Answer

(d) 51.6 %

Geo-Scientist Prelims 2020 Chemistry Q67: 0.05 molal aqueous solution of K₄[Fe(CN)₆] freezes at –0.26˚C. Its…

QuestionSolutions / degree of dissociation