The cell constant with 0.1 N KCl solution is found to be 0.98 cm⁻¹ and the resistance offered by 0.01 N HCl is 89 Ω. The specific conductance of HCl will be:

Question

Vimal Swarnkar · Accepted Answer

(b) 1.101 × 10⁻² Ω⁻¹ cm⁻¹. κ = cell constant / R = 0.98 cm⁻¹ / 89 Ω = 1.101 × 10⁻² Ω⁻¹ cm⁻¹ → (b). The cell constant found with KCl applies to any solution in the same cell.

Answer

(a) 1.101 × 10² Ω⁻¹ cm⁻¹

Answer

(c) 2.202 × 10⁻³ Ω⁻¹ cm⁻¹

Answer

(d) 2.202 × 10³ Ω⁻¹ cm⁻¹

Geo-Scientist Prelims 2020 Chemistry Q71: The cell constant with 0.1 N KCl solution is found to be 0.98 cm⁻¹…

QuestionElectrochemistry / conductance