When HCl is titrated against NaOH, the conductance at the end point is:

Question

Vimal Swarnkar · Accepted Answer

(b) Minimum. Fast H⁺ (λ° ≈ 350) is replaced by slow Na⁺ (≈ 50): conductance falls to the end point, then rises as excess OH⁻ (≈ 198) is added. V-shaped curve → minimum at the end point → (b).

Answer

(a) Zero

Answer

(c) Maximum

Answer

(d) Infinite

Geo-Scientist Prelims 2020 Chemistry Q79: When HCl is titrated against NaOH, the conductance at the end point…

QuestionElectrochemistry / conductometric titration