QuestionStereochemistry / counting isomers
The total number of stereoisomers possible for the given compound is:

- (a) 4
- (b) 6
- (c) 8
- (d) 10
Answer: (a) 4
ClCH₂CH=CH–CH=CHCH₂CH₃ has two stereogenic C=C with different ends (no stereocentre). Unsymmetrical, so 2² = 4 (EE, EZ, ZE, ZZ) → (a).