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Indian Forest Service (Mains)

Chemistry optional

  • 2 papers
  • 200 marks each
  • 3 h per paper

Paper I covers physical and inorganic chemistry.

Indian Forest Service (Mains), Chemistry optional · 2022 · Paper I

Q1(e). Activity coefficient of potassium ferricyanide

Question

Calculate the mean ionic activity coefficient of 0.002 M aqueous solution of potassium ferricyanide at 25 °C. (Given A = 0.509.)

Answer in brief

The Debye–Hückel limiting-law estimate is γ± ≈ 0.680.

Key points

  • Complete dissociation gives K₃[Fe(CN)₆] → 3K⁺ + [Fe(CN)₆]³⁻; thus c₊ = 0.006 M and c₋ = 0.002 M.
  • The ionic strength is I = ½Σcᵢzᵢ² = ½[0.006(1)² + 0.002(−3)²] = 0.012 mol L⁻¹.
  • Taking the stoichiometric mean of the individual limiting laws gives log₁₀γ± = −3A√I.
  • Therefore log₁₀γ± = −3(0.509)√0.012 = −0.16727, so γ± = 0.6803.

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(e), 2022 Paper I: solution pages 5 and 6
Solution pages 5 and 6 of 24

CoversDebye–Hückel limiting lawmean ionic activity coefficientionic strengthpotassium ferricyanide

All parts of Question 1