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Indian Forest Service (Mains)

Chemistry optional

  • 2 papers
  • 200 marks each
  • 3 h per paper

Paper II covers organic chemistry and spectroscopy.

Indian Forest Service (Mains), Chemistry optional · 2016 · Paper II

Q1(g). 6,6-Dimethylfulvene, phenyllithium and acetaldehyde

Question

Write the products formed in the following reaction sequence:
[structure] → (PhLi, Dry ether) A → ((i) MeCHO, (ii) H₃O⁺) B

Answer in brief

A = lithium (2-phenylpropan-2-yl)cyclopentadienide ; B = the secondary carbinol CH₃CH(OH)-C₅H₄-C(CH₃)₂Ph. If B is warmed with acid it loses water: the alternative answer after dehydration is 6-methyl-3-(2-phenylpropan-2-yl)fulvene.

Key points

  • PhLi delivers Ph⁻ to the electrophilic C-6; the π pair moves into the ring. A = lithium (2-phenylpropan-2-yl)cyclopentadienide, an aromatic 6π anion.
  • A is a carbon nucleophile (like an enolate). It adds to the C=O of acetaldehyde at the ring carbon remote from the bulky cumyl group (1,3-relation); H₃O⁺ gives the secondary alcohol.
  • B = 1-[3-(2-phenylpropan-2-yl)cyclopenta-1,3-dien-1-yl]ethan-1-ol, C₁₆H₂₀O; the ring double bonds shift by [1,5]-H shifts, so double-bond isomers interconvert.
  • With warm acid or base, B loses water to give a new 6-methylfulvene carrying the cumyl group on the ring (Thiele-type condensation).

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(g), 2016 Paper II: solution pages 5 and 6
Solution pages 5 and 6 of 31

Coversfulvenearomatic cyclopentadienideelectrophilic C-6secondary alcohol