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Indian Forest Service (Mains)

Chemistry optional

  • 2 papers
  • 200 marks each
  • 3 h per paper

Paper II covers organic chemistry and spectroscopy.

Indian Forest Service (Mains), Chemistry optional · 2016 · Paper II

Q1(h). Pinacol rearrangement with ring expansion

Question

Write the product and mechanism of the reaction:
[structure] → (H⁺) ?

Answer in brief

Pinacol rearrangement with ring expansion gives spiro[3.4]octan-5-one .

Key points

  • H⁺ protonates one OH; loss of H₂O (rate-determining) gives a tertiary carbocation on a cyclobutane carbon.
  • A ring C–C bond of the other cyclobutane migrates to C⁺ (1,2-shift). That ring becomes five-membered, and the carbon carrying OH becomes C⁺ stabilised by O.
  • Driving forces: relief of cyclobutane strain and formation of the oxocarbenium ion (all atoms with octets), which loses H⁺ to give C=O.
  • The cation's own ring is kept, so the product is a spiro ketone with C=O next to the spiro carbon: C₈H₁₄O₂ → C₈H₁₂O + H₂O.

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(h), 2016 Paper II: solution pages 7 and 8
Solution pages 7 and 8 of 31

Coverspinacol rearrangementrate-determiningtertiary carbocationfive-memberedrelief of cyclobutane strain