Indian Forest Service (Mains), Chemistry optional · 2016 · Paper II
Q1(h). Pinacol rearrangement with ring expansion
Question
Write the product and mechanism of the reaction:
[structure] → (H⁺) ?
Answer in brief
Pinacol rearrangement with ring expansion gives spiro[3.4]octan-5-one .
Key points
- H⁺ protonates one OH; loss of H₂O (rate-determining) gives a tertiary carbocation on a cyclobutane carbon.
- A ring C–C bond of the other cyclobutane migrates to C⁺ (1,2-shift). That ring becomes five-membered, and the carbon carrying OH becomes C⁺ stabilised by O.
- Driving forces: relief of cyclobutane strain and formation of the oxocarbenium ion (all atoms with octets), which loses H⁺ to give C=O.
- The cation's own ring is kept, so the product is a spiro ketone with C=O next to the spiro carbon: C₈H₁₄O₂ → C₈H₁₂O + H₂O.
The full model answer
As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Topic notes: molecular rearrangements, with every Civil Services, IFoS and Geo-Scientist PYQ →
Coverspinacol rearrangementrate-determiningtertiary carbocationfive-memberedrelief of cyclobutane strain
All parts of Question 1
- 1(a) Aromatic, antiaromatic or non-aromatic5 marks
- 1(b) Crossover experiments5 marks
- 1(c) Quinuclidine against triethylamine with ethyl iodide5 marks
- 1(d) Order of carbocation stability5 marks
- 1(e) Basicity of pyrrole, triethylamine and pyridine5 marks
- 1(f) Saytzeff and Hofmann eliminations5 marks
- 1(g) 6,6-Dimethylfulvene, phenyllithium and acetaldehyde5 marks
- 1(h) Pinacol rearrangement with ring expansion5 marks