Q1(h). Organolithium and Baeyer–Villiger sequence
Identify P, Q and R from the decalin carboxylic acid using (1) MeLi/EtOH, H₂O; (2) PhCOOOH; (3) NaOH/H₂O, reflux, then acid. [structure of the decalin carboxylic acid given in the paper]
Answer in brief
As printed, ethanol quenches MeLi; under the likely intended dry-ether conditions P is the methyl ketone, Q the decalinyl acetate and R the corresponding alcohol.
Key points
- In dry ether, excess MeLi first deprotonates DCO₂H and then adds to its lithium carboxylate; hydrolysis gives DCOCH₃.
- Perbenzoic acid forms a Criegee intermediate; the secondary decalinyl group migrates rather than methyl, yielding D–OCOCH₃ with retention of configuration.
- Base hydrolysis cleaves the acetate at its acyl centre, releasing D–OH after work-up.
- Literal ethanol gives MeLi + EtOH → CH₄ + LiOEt, so the sequence requires correcting EtOH to a dry ethereal solvent.
The full model answer
As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Topic notes: molecular rearrangements, with every Civil Services, IFoS and Geo-Scientist PYQ →
CoversBaeyer–Villiger oxidationmethyllithiumCriegee intermediatemigratory aptitudemethyl ketone from carboxylic acid
All parts of Question 1
- 1(a) Pyridine versus imidazole5 marks
- 1(b) Cyanide addition to a hindered enone5 marks
- 1(c) Tracing the nitrile carbon5 marks
- 1(d) Dichlorocarbene trapping5 marks
- 1(e) Substituent effects on aryl negative charge5 marks
- 1(f) Why DMSO accelerates many SN2 reactions5 marks
- 1(g) Rearrangement during silver-assisted solvolysis5 marks
- 1(h) Organolithium and Baeyer–Villiger sequence5 marks