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Indian Forest Service (Mains)

Chemistry optional

  • 2 papers
  • 200 marks each
  • 3 h per paper

Paper II covers organic chemistry and spectroscopy.

Indian Forest Service (Mains), Chemistry optional · 2022 · Paper II

Q1(h). Organolithium and Baeyer–Villiger sequence

Question

Identify P, Q and R from the decalin carboxylic acid using (1) MeLi/EtOH, H₂O; (2) PhCOOOH; (3) NaOH/H₂O, reflux, then acid. [structure of the decalin carboxylic acid given in the paper]

Answer in brief

As printed, ethanol quenches MeLi; under the likely intended dry-ether conditions P is the methyl ketone, Q the decalinyl acetate and R the corresponding alcohol.

Key points

  • In dry ether, excess MeLi first deprotonates DCO₂H and then adds to its lithium carboxylate; hydrolysis gives DCOCH₃.
  • Perbenzoic acid forms a Criegee intermediate; the secondary decalinyl group migrates rather than methyl, yielding D–OCOCH₃ with retention of configuration.
  • Base hydrolysis cleaves the acetate at its acyl centre, releasing D–OH after work-up.
  • Literal ethanol gives MeLi + EtOH → CH₄ + LiOEt, so the sequence requires correcting EtOH to a dry ethereal solvent.

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(h), 2022 Paper II: solution pages 9 and 10
Solution pages 9 and 10 of 34

CoversBaeyer–Villiger oxidationmethyllithiumCriegee intermediatemigratory aptitudemethyl ketone from carboxylic acid