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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper I covers physical and inorganic chemistry.

UPSC Civil Services (Mains), Chemistry optional · 2019 · Paper I

Q1(a)(i). Covalent character of NaBr and MgBr₂

  • 5 marks
  • Answered
Question

In which of the following compounds do the bonds have greater covalent character:
(a) NaBr or (b) MgBr₂ ?
Give reasons to support your answer.

Answer in brief

MgBr₂. The small, doubly charged Mg²+ ion polarises the large Br⁻ ion much more than Na⁺ does (Fajans' rules).

Key points

  • the comparison rests only on the cation's polarising power, which grows with charge and falls with size.
  • Na⁺ 102 pm, charge +1; Mg²+ 72 pm, charge +2 (six-coordinate radii). The charge density z/r² of Mg²+ is about 4 times that of Na⁺.
  • the large, soft Br⁻ cloud is drawn towards Mg²+; electron density builds up between the nuclei. This sharing of electron density is covalent character.
  • Δχ (Pauling) Na–Br = 2.96 − 0.93 = 2.03; Mg–Br = 2.96 − 1.31 = 1.65. A smaller difference means a less ionic bond.

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

  1. Same anion: the comparison rests only on the cation's polarising power, which grows with charge and falls with size.
  2. Size and charge: Na⁺ 102 pm, charge +1; Mg²+ 72 pm, charge +2 (six-coordinate radii). The charge density z/r² of Mg²+ is about 4 times that of Na⁺.
  3. Polarisation: the large, soft Br⁻ cloud is drawn towards Mg²+; electron density builds up between the nuclei. This sharing of electron density is covalent character.
  4. Electronegativity: Δχ (Pauling) Na–Br = 2.96 − 0.93 = 2.03; Mg–Br = 2.96 − 1.31 = 1.65. A smaller difference means a less ionic bond.
  5. Evidence: NaBr has the rock-salt structure; MgBr₂ has a layer structure and dissolves in ether and alcohols, typical of partly covalent halides.

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Model answer to Q1(a)(i), 2019 Paper I: solution page 2
Solution page 2 of 40