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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper I covers physical and inorganic chemistry.

UPSC Civil Services (Mains), Chemistry optional · 2019 · Paper I

Q6(c). Tetrasulfur tetranitride: preparation, structure, action of chlorine

  • 15 marks
  • Answered
Question

How tetrasulphur tetranitride (S₄N₄) is prepared? Present its structure. What happens when S₄N₄ is subjected to chlorine?

Answer in brief

6SCl₂ + 16NH₃ → S₄N₄ + 1/4S₈ + 12NH₄Cl. S₄N₄ is a cradle-shaped eight-membered ring: four coplanar N atoms with pairs of S atoms above and below, the S···S pairs at 258 pm. Chlorine cleaves the cage to trithiazyl trichloride: 3S₄N₄ + 6Cl₂ → 4(NSCl)₃.

Key points

  • Ammonia is passed into a solution of sulfur dichloride (or disulfur dichloride) in an inert solvent (CCl₄): 3pt] 6SCl₂ + 16NH₃ → S₄N₄ + 1/4S₈ + 12NH₄Cl (or 6S₂Cl₂ + 16NH₃ → S₄N₄ + S₈ + 12NH₄Cl) 3pt] NH₄Cl is filtered off and…
  • S₄N₄ is endergonic (Δ_fG°=+536 kJ mol⁻¹) and may detonate on shock or heating; it is handled in small amounts.
  • the four N atoms lie in one plane (a square); the four S atoms form a flattened tetrahedron, two above and two below the plane.
  • The two S atoms on each side are only 258 pm apart, far less than the van der Waals contact: a weak transannular S···S bond. All S–N bonds are equal, so the π electrons are delocalised round the ring.

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

Preparation

  1. Ammonia is passed into a solution of sulfur dichloride (or disulfur dichloride) in an inert solvent (CCl₄): 3pt] 6SCl₂ + 16NH₃ → S₄N₄ + 1/4S₈ + 12NH₄Cl (or 6S₂Cl₂ + 16NH₃ → S₄N₄ + S₈ + 12NH₄Cl) 3pt] NH₄Cl is filtered off and S₄N₄ crystallised as orange-yellow crystals.
  2. S₄N₄ is endergonic (Δ_fG°=+536 kJ mol⁻¹) and may detonate on shock or heating; it is handled in small amounts.

Structure

  1. An eight-membered S–N ring, cradle-shaped: the four N atoms lie in one plane (a square); the four S atoms form a flattened tetrahedron, two above and two below the plane.
  2. The two S atoms on each side are only 258 pm apart, far less than the van der Waals contact: a weak transannular S···S bond. All S–N bonds are equal, so the π electrons are delocalised round the ring.
  3. Lewis acids (BF₃, SbF₅, SO₃) form 1:1 adducts through one N atom, and the ring rearranges.

Action of chlorine

  1. Chlorine passed into S₄N₄ in CCl₄ oxidises and cleaves the cage; the fragments rearrange to trithiazyl trichloride: 3pt] 3S₄N₄ + 6Cl₂ → 4(NSCl)₃ 3pt] Check: S 12 = 12, N 12 = 12, Cl 12 = 12.
  2. (NSCl)₃ (S₃N₃Cl₃) is a six-membered ring of alternating S and N in a chair form, one Cl on each S (S(IV)). On warming it dissociates to monomeric thiazyl chloride, NSCl.

Application. S₄N₄ is the starting point of sulfur–nitrogen chemistry: passed over hot silver wool it gives S₂N₂, which polymerises to (SN)ₓ, a metallic polymer that becomes superconducting at very low temperature.

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Model answer to Q6(c), 2019 Paper I: solution page 29
Solution page 29 of 40

All parts of Question 6