Q7(a). Maximum number of coexisting phases from the phase rule
Predict the maximum number of phases that can coexist for
(i) 3 component system at constant P & T
(ii) 2 component system at constant T
(iii) one component system at constant T & P
Answer in brief
(i) 3 (ii) 3 (iii) 1
Key points
- (i) C=3, P and T fixed: F”=C-P=3-P. Setting F”=0: Pₘₐₓ=3 4pt] Example: in a ternary (triangular) diagram at fixed T and P, a three-phase triangle, such as three mutually saturated liquid or solid phases; the compositions of…
- (ii) C=2, T fixed: F'=C-P+1=3-P. Setting F'=0: Pₘₐₓ=3 4pt] At the chosen temperature three phases coexist only at one definite pressure, for example liquid A + liquid B + vapour for two partly miscible liquids, or ice + salt +…
- (iii) C=1, T and P fixed: F”=C-P=1-P. Setting F”=0: Pₘₐₓ=1 4pt] For a pure substance, choosing T and P independently fixes a point in one area of the phase diagram: only one phase is stable (water at 25°C and 1 atm is liquid…
- two phases of a one-component system coexist only along a line (T and P linked, F=1), and three only at the triple point (F=0), which requires both T and P to be left unfixed so the system can choose them. Fixing them in…
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
Principle: Gibbs phase rule, F=C-P+2; the 2 counts temperature and pressure. When one of them is held fixed, the rule becomes F'=C-P+1; with both fixed, F”=C-P. The number of phases is largest when no freedom is left, F=0 (degrees of freedom cannot be negative).
- (i) C=3, P and T fixed: F”=C-P=3-P. Setting F”=0: Pₘₐₓ=3 4pt] Example: in a ternary (triangular) diagram at fixed T and P, a three-phase triangle, such as three mutually saturated liquid or solid phases; the compositions of all three phases are then fixed.
- (ii) C=2, T fixed: F'=C-P+1=3-P. Setting F'=0: Pₘₐₓ=3 4pt] At the chosen temperature three phases coexist only at one definite pressure, for example liquid A + liquid B + vapour for two partly miscible liquids, or ice + salt + saturated solution in a salt–water system at its eutectic temperature.
- (iii) C=1, T and P fixed: F”=C-P=1-P. Setting F”=0: Pₘₐₓ=1 4pt] For a pure substance, choosing T and P independently fixes a point in one area of the phase diagram: only one phase is stable (water at 25°C and 1 atm is liquid only).
- Contrast: two phases of a one-component system coexist only along a line (T and P linked, F=1), and three only at the triple point (F=0), which requires both T and P to be left unfixed so the system can choose them. Fixing them in advance leaves room for one phase.
- Unconstrained maxima: without fixing anything the maximum is C+2: 3 for one component, 4 for two components, 5 for three. Each condition imposed removes one phase from the maximum.
Application. the phase rule fixes the number of phases at invariant points used in metallurgy and geology: a binary alloy at its eutectic (solid A + solid B + melt at fixed pressure) solidifies at constant temperature, and mineral assemblages in rocks rarely exceed the phase-rule limit.
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All parts of Question 7
- 7(a) Maximum number of coexisting phases from the phase rule15 marks
- 7(b) Tetragonal distortion and the square-planar limit15 marks
- 7(c) Why N₂⁺ is weaker but O₂⁺ stronger than the neutral molecule10 marks
- 7(d) A cell for AgBr(s) → Ag⁺ + Br⁻10 marks