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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper II covers organic chemistry and spectroscopy.

UPSC Civil Services (Mains), Chemistry optional · 2017 · Paper II

Q1(c). Diethylamine and 2-fluoro-1-acetylcyclohexene: addition–elimination

  • 10 marks
  • Answered
Question

Write the product of the following reaction and depict the mechanistic pathway for its formation.
[structure] → (Et₂NH)

Answer in brief

Product: 1-[2-(diethylamino)cyclohex-1-en-1-yl]ethan-1-one, an enaminone (C₁₂H₂₁NO), formed by conjugate addition of Et₂NH followed by elimination of F⁻.

Key points

  • The nitrogen lone pair of Et₂NH attacks C-2 (Michael-type addition); the π electrons move to the enolate oxygen. This is the slow step.
  • The tetrahedral C-2 now carries F and NHEt₂⁺. The enolate pushes back to re-form C=C and F⁻ leaves; a second amine (or the fluoride) removes H⁺ from nitrogen.
  • Fluorine is a good leaving group here because C–F breaking is not rate-limiting; its strong -I effect makes C-2 more electrophilic in step 1.
  • The product is stabilised by push–pull conjugation N-C=C-C=O <→ N+=C-C=C-O⁻ (a vinylogous amide), so substitution, not simple addition, is observed.

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

Introduction. The C=C is conjugated with C=O, so its β-carbon (C-2, bearing F) is electrophilic. A nucleophile adds there (conjugate addition) and fluoride, now on an sp³ carbon next to an enolate, is expelled. This is nucleophilic vinylic substitution by addition–elimination (AdN–E).

Scheme: Addition of the amine to the β-carbon, then loss of fluoride re-forms the C=C.

  1. The nitrogen lone pair of Et₂NH attacks C-2 (Michael-type addition); the π electrons move to the enolate oxygen. This is the slow step.
  2. The tetrahedral C-2 now carries F and NHEt₂⁺. The enolate pushes back to re-form C=C and F⁻ leaves; a second amine (or the fluoride) removes H⁺ from nitrogen.
  3. Fluorine is a good leaving group here because C–F breaking is not rate-limiting; its strong -I effect makes C-2 more electrophilic in step 1.
  4. The product is stabilised by push–pull conjugation N-C=C-C=O <→ N+=C-C=C-O⁻ (a vinylogous amide), so substitution, not simple addition, is observed.

Conclusion. Product: 1-[2-(diethylamino)cyclohex-1-en-1-yl]ethan-1-one, an enaminone (C₁₂H₂₁NO), formed by conjugate addition of Et₂NH followed by elimination of F⁻.

Application. β-Halo enones and β-chlorovinyl ketones react with amines in this way; enaminones made so are building blocks for pyrazoles, pyrimidines and quinolones.

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Model answer to Q1(c), 2017 Paper II: solution page 3
Solution page 3 of 23