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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper II covers organic chemistry and spectroscopy.

UPSC Civil Services (Mains), Chemistry optional · 2017 · Paper II

Q1(e). Electrocyclic closure of (2E,4E)-hexa-2,4-diene: FMO

  • 10 marks
  • Answered
Question

Write the structure of the product with proper stereochemical outcome, in each of the following reactions and justify your answers with the help of FMO theory.
⇌ (hν) [structure] ⇌ (Δ)

Answer in brief

hν: disrotatory closure gives cis-3,4-dimethylcyclobut-1-ene; Δ: conrotatory closure gives trans-3,4-dimethylcyclobut-1-ene. The outcome follows from the HOMO symmetry (ψ₃ excited, ψ₂ ground state).

Key points

  • Thermal (Δ). Ground-state HOMO of butadiene is ψ₂: the terminal lobes on the same face have opposite phase. Bonding overlap needs both termini to turn the same way: conrotatory. In the (E,E) diene both methyls point outward;…
  • Photochemical (hν). One electron is promoted, the HOMO is ψ₃; its terminal lobes on the same face have the same phase. Closure is disrotatory: one methyl turns up, the other also up relative to the ring plane, giving…
  • Both are reversible as printed. Thermally the equilibrium lies on the diene side (ring strain), so trans-3,4-dimethylcyclobutene opens conrotatorily back to (E,E)-hexadiene; photochemically the cyclobutene accumulates because…

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

Reading of the question: the diene is printed s-cis with both double bonds E, i.e. (2E,4E)-hexa-2,4-diene; each side gives a 3,4-dimethylcyclobutene.

Introduction. Ring closure of a 1,3-diene to a cyclobutene is a 4π electrocyclic reaction. In the FMO method the stereochemistry is decided by the symmetry of the HOMO at the two termini (C-2 and C-5 here): the termini rotate so that lobes of the same phase overlap to form the new σ bond.

Figure: Terminal lobes of the HOMO: shaded and open lobes have opposite phase.

  1. Thermal (Δ). Ground-state HOMO of butadiene is ψ₂: the terminal lobes on the same face have opposite phase. Bonding overlap needs both termini to turn the same way: conrotatory. In the (E,E) diene both methyls point outward; one turns up and one down, so they end on opposite faces: trans-3,4-dimethylcyclobutene.
  2. Photochemical (hν). One electron is promoted, the HOMO is ψ₃; its terminal lobes on the same face have the same phase. Closure is disrotatory: one methyl turns up, the other also up relative to the ring plane, giving cis-3,4-dimethylcyclobutene.
  3. Both are reversible as printed. Thermally the equilibrium lies on the diene side (ring strain), so trans-3,4-dimethylcyclobutene opens conrotatorily back to (E,E)-hexadiene; photochemically the cyclobutene accumulates because it does not absorb at the wavelength used.

Scheme: Products drawn with the methyl groups on wedge and hash bonds.

Conclusion. hν: disrotatory closure gives cis-3,4-dimethylcyclobut-1-ene; Δ: conrotatory closure gives trans-3,4-dimethylcyclobut-1-ene. The outcome follows from the HOMO symmetry (ψ₃ excited, ψ₂ ground state).

Application. The same con/dis rule fixes the ring-junction stereochemistry in the photochemical ring-opening of provitamin D (7-dehydrocholesterol) and in the Nazarov cyclisation.

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Model answer to Q1(e), 2017 Paper II: solution page 5
Solution page 5 of 23