Q3(a). Acetylacetone with MeMgI; conversion to hexane-2,4-dione
What happens when 2,4-pentadione is treated with one equivalent of MeMgI? How can you convert the mentioned dione to 2,4-hexadione?
Answer in brief
With one equivalent of MeMgI acetylacetone only loses its active H: CH₄ and a chelated magnesium enolate form. Hexane-2,4-dione is made by forming the dianion (2 NaNH₂/NH₃ or 2 LDA) and methylating the terminal carbon with CH₃I.
Key points
- CH₃⁻ of MeMgI removes the active methylene H; methane is evolved (one mole per mole of dione; this is the Zerewitinoff estimation of active H).
- The product is the magnesium enolate CH₃C(OMgI)=CHCOCH₃, held as a six-membered chelate. It is delocalised and no longer electrophilic, so no tertiary alcohol forms; on acid work-up acetylacetone is recovered.
- The first equivalent of base removes the central H; the second removes a terminal CH₃ hydrogen, giving the dianion.
- The terminal carbanion is the less stabilised, more basic and more nucleophilic site, so one equivalent of CH₃I alkylates only there (γ-alkylation, Hauser).
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
Reading of the question: “2,4-pentadione” is pentane-2,4-dione (acetylacetone) and “2,4-hexadione” is hexane-2,4-dione.
Introduction. The CH₂ between the two carbonyl groups of acetylacetone is strongly acidic, because its anion is shared by both C=O groups. A Grignard reagent is a much stronger base than it is a nucleophile towards such a ketone.
(i) One equivalent of MeMgI
Scheme: The Grignard reagent is protonated; no C=O addition takes place.
- CH₃⁻ of MeMgI removes the active methylene H; methane is evolved (one mole per mole of dione; this is the Zerewitinoff estimation of active H).
- The product is the magnesium enolate CH₃C(OMgI)=CHCOCH₃, held as a six-membered chelate. It is delocalised and no longer electrophilic, so no tertiary alcohol forms; on acid work-up acetylacetone is recovered.
(ii) To hexane-2,4-dione: alkylation of the dianion
Scheme: The second, more basic carbanion is formed at a terminal CH₃ and is alkylated there.
- The first equivalent of base removes the central H; the second removes a terminal CH₃ hydrogen, giving the dianion.
- The terminal carbanion is the less stabilised, more basic and more nucleophilic site, so one equivalent of CH₃I alkylates only there (γ-alkylation, Hauser).
- Acid work-up: CH₃COCH₂COCH₂CH₃, hexane-2,4-dione. (Monoalkylation of the ordinary anion with CH₃I would put the methyl on C-3 instead: 3-methylpentane-2,4-dione.)
Conclusion. With one equivalent of MeMgI acetylacetone only loses its active H: CH₄ and a chelated magnesium enolate form. Hexane-2,4-dione is made by forming the dianion (2 NaNH₂/NH₃ or 2 LDA) and methylating the terminal carbon with CH₃I.
Application. Dianion alkylation of β-dicarbonyl compounds (Hauser, Weiler) is a standard way to lengthen the chain at the γ-carbon, used in the synthesis of polyketide fragments.
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All parts of Question 3
- 3(a) Acetylacetone with MeMgI; conversion to hexane-2,4-dione10 marks
- 3(b) Tertiary alcohol with two identical alkyl groups; Lucas test10 marks
- 3(c) Tosylation, S_N₂ by acetate and hydrolysis: a Walden cycle10 marks
- 3(d) Intramolecular Cannizzaro of furylglyoxal; furoin10 marks
- 3(e) Morpholine and 4-fluorophenyl methyl sulfone: S_NAr10 marks