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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper II covers organic chemistry and spectroscopy.

UPSC Civil Services (Mains), Chemistry optional · 2017 · Paper II

Q3(e). Morpholine and 4-fluorophenyl methyl sulfone: S_NAr

  • 10 marks
  • Answered
Question

Write the structure of the product of the following reaction and depict the mechanism.
[structure] → ( [structure], DMSO, K₂CO₃)

Answer in brief

Product: 4-[4-(methylsulfonyl)phenyl]morpholine, C₁₁H₁₅NO₃S, by SNAr (addition–elimination through a Meisenheimer complex).

Key points

  • The N of morpholine attacks C-1 (bearing F) perpendicular to the ring. The ring loses aromaticity; the negative charge is delocalised to C-2, C-4, C-6 and onto the sulfonyl group at C-4: the Meisenheimer complex. This addition…
  • Fluoride leaves and aromaticity returns; K₂CO₃ removes the N-H⁺ proton and neutralises HF. DMSO (polar aprotic) leaves the amine unsolvated and reactive.
  • F is the best leaving group in SNAr (F > Cl > Br > I) because C–F breaking is not rate-limiting and the strong -I effect of F speeds the addition.

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

Introduction. An aryl fluoride carrying a strong electron-withdrawing group para to F undergoes nucleophilic aromatic substitution by addition–elimination (SNAr). The SO₂Me group stabilises the anionic intermediate.

Scheme: Addition of the amine to C–F, then loss of fluoride restores the aromatic ring.

  1. The N of morpholine attacks C-1 (bearing F) perpendicular to the ring. The ring loses aromaticity; the negative charge is delocalised to C-2, C-4, C-6 and onto the sulfonyl group at C-4: the Meisenheimer complex. This addition is the rate-determining step.
  2. Fluoride leaves and aromaticity returns; K₂CO₃ removes the N-H⁺ proton and neutralises HF. DMSO (polar aprotic) leaves the amine unsolvated and reactive.
  3. F is the best leaving group in SNAr (F > Cl > Br > I) because C–F breaking is not rate-limiting and the strong -I effect of F speeds the addition.

Conclusion. Product: 4-[4-(methylsulfonyl)phenyl]morpholine, C₁₁H₁₅NO₃S, by SNAr (addition–elimination through a Meisenheimer complex).

Application. SNAr of activated aryl fluorides with morpholine and piperazine is used industrially to make drugs such as linezolid and the fluoroquinolone antibiotics.

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Model answer to Q3(e), 2017 Paper II: solution page 13
Solution page 13 of 23