Q4(b). 3-Bromoanisole and amide ion: benzyne regiochemistry
Predict the product(s) with mechanism and justify your answer.
[structure] → (⁻NH₂ / liq. NH₃)
Answer in brief
m-Anisidine (3-methoxyaniline) is the only product, via 3-methoxybenzyne: H-2 is removed because it is flanked by two -I groups, and NH₂⁻ adds to C-1 so that the aryl anion sits ortho to OMe.
Key points
- Which benzyne. Two hydrogens are ortho to Br: H-2 (between OMe and Br) and H-4. H-2 is more acidic: both the -I effect of OMe and of Br act on it. Removal of H-2 and loss of Br⁻ give 3-methoxybenzyne (the triple bond between…
- Where NH₂⁻ adds. Addition at C-1 places the new carbanion on C-2, ortho to OMe, where the -I effect of oxygen stabilises it (the sp² lone pair is in the ring plane, so resonance does not matter). Addition at C-2 would put the…
- Protonation by NH₃ gives the amine and regenerates NH₂⁻.
- Both steps point the same way, so only one product forms: 3-methoxyaniline. The amino group enters at the carbon that carried Br (cine substitution does not happen here).
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
Introduction. Aryl halides without activating groups react with NH₂⁻ in liquid ammonia by elimination–addition: benzyne is formed first, and NH₂⁻ then adds to it. The positions of H removal and of NH₂⁻ addition are both controlled by the inductive effect of OMe.
Scheme: H-2 (between OMe and Br) is removed; NH₂⁻ adds meta to OMe.
- Which benzyne. Two hydrogens are ortho to Br: H-2 (between OMe and Br) and H-4. H-2 is more acidic: both the -I effect of OMe and of Br act on it. Removal of H-2 and loss of Br⁻ give 3-methoxybenzyne (the triple bond between C-1 and C-2, OMe on C-3).
- Where NH₂⁻ adds. Addition at C-1 places the new carbanion on C-2, ortho to OMe, where the -I effect of oxygen stabilises it (the sp² lone pair is in the ring plane, so resonance does not matter). Addition at C-2 would put the anion meta to OMe, far less stabilised.
- Protonation by NH₃ gives the amine and regenerates NH₂⁻.
- Both steps point the same way, so only one product forms: 3-methoxyaniline. The amino group enters at the carbon that carried Br (cine substitution does not happen here).
Conclusion. m-Anisidine (3-methoxyaniline) is the only product, via 3-methoxybenzyne: H-2 is removed because it is flanked by two -I groups, and NH₂⁻ adds to C-1 so that the aryl anion sits ortho to OMe.
Application. The same inductive control gives m-anisidine from o-bromoanisole as well; benzyne chemistry is used to make meta-substituted anilines that electrophilic substitution cannot give.
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All parts of Question 4
- 4(a) Epoxidation, then intramolecular opening by a nitrile anion10 marks
- 4(b) 3-Bromoanisole and amide ion: benzyne regiochemistry10 marks
- 4(c) SeO₂ allylic oxidation; dihydroxylation and selective oxidation10 marks
- 4(d) E2 of menthyl and neomenthyl chlorides: anti-periplanar requirement10 marks
- 4(e) But-2-yne to cis- and trans-but-2-ene10 marks