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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper II covers organic chemistry and spectroscopy.

UPSC Civil Services (Mains), Chemistry optional · 2017 · Paper II

Q4(c). SeO₂ allylic oxidation; dihydroxylation and selective oxidation

  • 10 marks
  • Answered
Question

Write the reagent(s) for the following conversions and write the mechanism for reaction (i).
(i) [structure] [structure]
(ii) [structure] [cis-diol] [structure]

Answer in brief

(i) SeO₂/t-BuOOH: ene reaction then [2,3]-sigmatropic shift gives (E)-2-methylhept-2-en-1-ol. (ii) OsO₄/NMO, then Swern (or PCC) oxidation: 2-hydroxy-2-methylcyclohexan-1-one.

Key points

  • Ene reaction. SeO₂ (as O=Se=O) acts as the enophile: the allylic H of the methyl trans to the chain is transferred to O while Se bonds to C-3; the C=C shifts. Product: an allylseleninic acid.
  • [2,3]-Sigmatropic shift. The Se-C₃ bond and the new C=C reorganise through a five-membered cyclic TS: the C=C returns to C2=C3 and oxygen ends on the methyl carbon, as a selenite ester C-O-Se-OH.
  • Hydrolysis gives the allylic alcohol and Se(II), which t-BuOOH reoxidises to SeO₂ (so only a catalytic amount is needed and over-oxidation to the aldehyde is limited).
  • the hydroxyl appears on the (E)-methyl, the one trans to the longer chain, because the ene TS with the chain pointing away is less crowded: product (E)-2-methylhept-2-en-1-ol.

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

Introduction. (i) is an allylic oxidation of a trisubstituted alkene: one of the gem-methyl groups becomes CH₂OH and the C=C stays in place. (ii) is a syn-dihydroxylation followed by oxidation of only the secondary OH.

(i) Reagent: SeO₂ (catalytic) with t-BuOOH, CH₂Cl₂

  1. Ene reaction. SeO₂ (as O=Se=O) acts as the enophile: the allylic H of the methyl trans to the chain is transferred to O while Se bonds to C-3; the C=C shifts. Product: an allylseleninic acid.
  2. [2,3]-Sigmatropic shift. The Se-C₃ bond and the new C=C reorganise through a five-membered cyclic TS: the C=C returns to C2=C3 and oxygen ends on the methyl carbon, as a selenite ester C-O-Se-OH.
  3. Hydrolysis gives the allylic alcohol and Se(II), which t-BuOOH reoxidises to SeO₂ (so only a catalytic amount is needed and over-oxidation to the aldehyde is limited).
  4. Selectivity: the hydroxyl appears on the (E)-methyl, the one trans to the longer chain, because the ene TS with the chain pointing away is less crowded: product (E)-2-methylhept-2-en-1-ol.

Scheme: Ene reaction, [2,3]-sigmatropic shift and hydrolysis.

(ii) Reagents

  1. 1-Methylcyclohexene → cis-diol: OsO₄ (catalytic) with NMO (or cold, dilute alkaline KMnO₄); syn addition through a cyclic osmate ester gives cis-1-methylcyclohexane-1,2-diol.
  2. Diol → α-hydroxy ketone: oxidise the secondary OH only, with Swern reagent (DMSO, (COCl)₂, Et₃N, -78°C) or PCC. The tertiary OH has no C–H and is untouched; neutral conditions avoid C–C cleavage of the diol.

Conclusion. (i) SeO₂/t-BuOOH: ene reaction then [2,3]-sigmatropic shift gives (E)-2-methylhept-2-en-1-ol. (ii) OsO₄/NMO, then Swern (or PCC) oxidation: 2-hydroxy-2-methylcyclohexan-1-one.

Application. SeO₂ oxidation of the (E)-methyl of trisubstituted alkenes is used to make terpene allylic alcohols and aldehydes, for example in syntheses of geraniol-derived fragrances.

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Model answer to Q4(c), 2017 Paper II: book edition page 15
Book edition, page 15
Model answer to Q4(c), 2017 Paper II: book edition page 16
Book edition, page 16