Q7(c). Reagents: NaBH₄, LiAlH₄, Birch, SeO₂, Pb(OAc)₄
Write the structure of the major product formed in the following reactions and provide the mechanism:
(i) [structure] → (NaBH₄, EtOH) (ii) [structure] → ((i) LiAlH₄, (ii) H₂O) (iii) [structure] → (Na, NH₃ (l), ether, ethanol)
(iv) [structure] → (SeO₂) (v) [structure] → (Pb(OAc)₄)
Answer in brief
(i) Methyl 3-(hydroxymethyl)benzoate; (ii) trans-4-tert-butylcyclohexanol; (iii) 1-methoxycyclohexa-1,4-diene; (iv) the (E)-allylic alcohol RCH=C(CH₃)CH₂OH; (v) 2-cyano-1,4-benzoquinone.
Key points
- Na gives an electron to the ring (solvated electron in NH₃): radical anion.
- Ethanol protonates it ortho to OMe; for an electron donor the negative charge avoids the carbon bearing OMe.
- A second electron and a second proton give the non-conjugated diene; the OMe ends on a C=C.
- SeO₂ (Se=O as the enophile) takes an allylic H from the methyl group trans to R and forms an allylic seleninic acid, with the C=C moved.
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
Introduction. Five reagents chosen for selectivity: a mild hydride that leaves esters alone, a hydride whose stereochemistry is set by a conformationally locked ring, a dissolving-metal reduction of an arene, an allylic oxidation, and an oxidation of a hydroquinone.
(i) NaBH₄: aldehyde reduced, ester kept
BH₄⁻ transfers hydride to the more electrophilic aldehyde C=O; ethanol protonates the alkoxide. The ester carbonyl is stabilised by the lone pair of OMe and reacts far more slowly. Product: methyl 3-(hydroxymethyl)benzoate.
Scheme: Chemoselective reduction.
(ii) LiAlH₄ on 4-tert-butylcyclohexanone
The tert-butyl group is fixed equatorial and locks the chair. Small AlH₄⁻ attacks from the axial direction (torsional strain with the axial H atoms on C-2 and C-6 is smaller along this path), so the new OH is equatorial. Product: trans-4-tert-butylcyclohexan-1-ol (about 90 %), with about 10 % of the cis (axial OH) isomer. (Bulky L-Selectride attacks equatorially and gives mainly the cis alcohol.)
Scheme: Small hydrides give the thermodynamically favoured equatorial alcohol.
(iii) Birch reduction of anisole
- Na gives an electron to the ring (solvated electron in NH₃): radical anion.
- Ethanol protonates it ortho to OMe; for an electron donor the negative charge avoids the carbon bearing OMe.
- A second electron and a second proton give the non-conjugated diene; the OMe ends on a C=C.
Product: 1-methoxycyclohexa-1,4-diene (acid hydrolysis would give cyclohex-2-enone/cyclohex-3-enone).
Scheme: Electron-donating groups end on an unreduced C=C.
(iv) SeO₂ allylic oxidation
- Ene reaction: SeO₂ (Se=O as the enophile) takes an allylic H from the methyl group trans to R and forms an allylic seleninic acid, with the C=C moved.
- A [2,3]-sigmatropic rearrangement moves the C=C back and gives an allylic seleninate ester.
- Hydrolysis gives the allylic alcohol; further oxidation can give the aldehyde.
The oxidised carbon is the methyl trans to the larger group R (Bhalla–Sharpless rule), so the geometry is (E). Product: (E)-2-methyl-3-R-prop-2-en-1-ol, R-CH=C(CH₃)-CH₂OH (with some (E)-enal).
Scheme: The CH₃ trans to R becomes CH₂OH.
(v) Pb(OAc)₄ on 2-cyanohydroquinone
Lead tetra-acetate is a two-electron oxidant. One phenolic OH exchanges with an acetate on lead (ArO-Pb(OAc)₃); the O–Pb bond breaks heterolytically with loss of Pb(OAc)₂ and AcO⁻, and the second OH loses H⁺. The para-dihydroxy compound is oxidised to the para-quinone. Product: 2-cyano-1,4-benzoquinone (2-cyanocyclohexa-2,5-diene-1,4-dione).
Scheme: Hydroquinone to quinone: the electron-poor cyanoquinone is a strong dienophile and oxidant.
Conclusion. (i) Methyl 3-(hydroxymethyl)benzoate; (ii) trans-4-tert-butylcyclohexanol; (iii) 1-methoxycyclohexa-1,4-diene; (iv) the (E)-allylic alcohol RCH=C(CH₃)CH₂OH; (v) 2-cyano-1,4-benzoquinone.
Application. Birch reduction of anisoles is the key step in making 19-norsteroid oral contraceptives; SeO₂ allylic oxidation is used in terpene and vitamin synthesis; cyanoquinones (like DDQ) are dehydrogenating oxidants.
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All parts of Question 7
- 7(a) Stokes shift; why phosphorescence is slow10 marks
- 7(b) Norrish type I products; spin state in Norrish type II20 marks
- 7(c) Reagents: NaBH₄, LiAlH₄, Birch, SeO₂, Pb(OAc)₄20 marks