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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper II covers organic chemistry and spectroscopy.

UPSC Civil Services (Mains), Chemistry optional · 2026 · Paper II

Q8(a). Rotational constant; vibrational order; chelated C=O and OH

  • 15 marks
  • Answered
Question

(i) Calculate the rotational constant of a diatomic molecule if the moment of inertia is 13.97×10⁻⁴⁷ kg m². (Given: Planck's constant h = 6.626×10⁻³⁴ Js and velocity of light c = 2.998×10⁸ ms⁻¹)
(ii) Arrange the following molecules in increasing order of vibrational frequency (cm⁻¹): HF, HI, NO, CO
(iii) Explain the specific vibrational frequencies (C=O and -OH) in pentane-2,4-dione and 2-hydroxypropiophenone.

Answer in brief

(i) B = 200.4 m⁻¹ = 2.00 cm⁻¹. (ii) NO < CO < HI < HF. (iii) Chelation lowers C=O to about 1615 (enol of pentane-2,4-dione) and 1640 cm⁻¹ (2'-hydroxypropiophenone) and gives broad, dilution-independent O–H bands well below 3600 cm⁻¹.

Key points

  • Introduction. A rigid diatomic rotor has energy levels F(J)=BJ(J+1), with the rotational constant B (in cm⁻¹) fixed by the moment of inertia. A harmonic bond vibrates at ν=(1)/(2π c)√(k/μ): a stiff bond (large k) and light…
  • NO < CO < HI < HF NO and CO have heavy atoms (μ≈7 u), so even their strong multiple bonds vibrate at about 1900–2100 cm⁻¹; NO is lower than CO because its extra electron sits in a π^* orbital (bond order 2.5 against 3). The…

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

Introduction. A rigid diatomic rotor has energy levels F(J)=BJ(J+1), with the rotational constant B (in cm⁻¹) fixed by the moment of inertia. A harmonic bond vibrates at ν=(1)/(2π c)√(k/μ): a stiff bond (large k) and light atoms (small μ) give a high wavenumber.

(i) Rotational constant

Given: I = 13.97×10⁻⁴⁷ kg m²; h = 6.626×10⁻³⁴ J s; c = 2.998×10⁸ m s⁻¹.

B = (h)/(8π² I c)

B = 6.626×10⁻³⁴8×(3.1416)²×13.97×10⁻⁴⁷×2.998×10⁸ = 200.4 m⁻¹

B = 2.00 cm⁻¹ In frequency units B = h/8π² I = 6.01×10¹⁰ Hz. The lines of the pure rotational spectrum are spaced by 2B = 4.01 cm⁻¹. (A moment of inertia of this size is that of a molecule such as CO, B≈1.93 cm⁻¹.)

(ii) Order of vibrational wavenumbers

Moleculeμ (u)k (N m⁻¹)ν (cm⁻¹), fundamental
NO7.47about 15901876
CO6.86about 19002143
HI1.00about 3102230
HF0.96about 9703962

NO < CO < HI < HF NO and CO have heavy atoms (μ≈7 u), so even their strong multiple bonds vibrate at about 1900–2100 cm⁻¹; NO is lower than CO because its extra electron sits in a π^* orbital (bond order 2.5 against 3). The hydrogen halides have μ≈1 u, so even the weak H–I bond reaches 2230 cm⁻¹; HF combines the lightest μ with a strong bond and is highest.

(iii) Pentane-2,4-dione and 2'-hydroxypropiophenone

Reading of the question: “2-hydroxypropiophenone” is read as 2'-hydroxypropiophenone (OH ortho on the ring), the compound that, like the enol of pentane-2,4-dione, forms an intramolecular hydrogen bond to C=O.

Scheme: In both compounds an OH is hydrogen-bonded to C=O in a six-membered ring.

Pentane-2,4-dione is mostly enol (stabilised by conjugation and a strong intramolecular hydrogen bond). The chelated enol shows a strong broad band near 1615 cm⁻¹ (C=O, conjugated with C=C and H-bonded, coupled with the C=C stretch), and a very broad, weak O–H band spread over 2500–3200 cm⁻¹ (centred near 2750), instead of the sharp 3600 of a non-bonded OH. The minor diketo form shows two C=O bands near 1727 and 1707 cm⁻¹ (in- and out-of-phase stretching of the two C=O groups).

2'-Hydroxypropiophenone: the aryl ketone C=O (normally about 1685) is lowered to about 1640 cm⁻¹ by the chelating OH, and the O–H stretch appears as a broad band near 3000–3100 cm⁻¹. Both bands are unchanged on dilution (intramolecular H-bond), which distinguishes them from intermolecular hydrogen bonding.

Conclusion. (i) B = 200.4 m⁻¹ = 2.00 cm⁻¹. (ii) NO < CO < HI < HF. (iii) Chelation lowers C=O to about 1615 (enol of pentane-2,4-dione) and 1640 cm⁻¹ (2'-hydroxypropiophenone) and gives broad, dilution-independent O–H bands well below 3600 cm⁻¹.

Application. Rotational constants from microwave spectra give bond lengths (here r would follow from I=μ r²); chelated C=O and OH bands identify β-diketone ligands such as acac used in metal complexes and o-hydroxyaryl ketone UV absorbers in sunscreens and plastics.

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Model answer to Q8(a), 2026 Paper II: solution page 21
Solution page 21 of 26

All parts of Question 8