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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper II covers organic chemistry and spectroscopy.

UPSC Civil Services (Mains), Chemistry optional · 2026 · Paper II

Q8(b). 1H NMR: furfural, arenes, ethanol, nitroacetophenones

  • 15 marks
  • Answered
Question

(i) Discuss the spin-spin interactions and coupling constants in 1H NMR spectrum of furfuraldehyde.
(ii) Distinguish between (A) anthracene and phenanthrene, and (B) pure ethanol and ethanol in presence of trace amount of acidic impurity, based on 1H NMR spectra.
(iii) How can you differentiate between 2-nitroacetophenone and 3-nitroacetophenone based on approximate chemical shifts and spin-spin interactions? (Consider only ortho-coupling)

Answer in brief

(i) Furfural: three dd ring signals with J_(3,4)≈3.6, J_(4,5)≈1.7, J_(3,5)≈0.8 Hz, and CHO at δ 9.65. (ii) Anthracene has three signals with a low-field singlet; phenanthrene five, with a low-field bay doublet. Pure ethanol shows an OH triplet; with acid the OH is a singlet and CH₂ a quartet. (iii) Only 3-nitroacetophenone shows an isolated low-field singlet (H-2).

Key points

  • δ 9.65 (s; a small 0.8 Hz long-range coupling may be seen).
  • H-5 (next to O): δ 7.70, dd, J_(4,5)≈1.7, J_(3,5)≈0.8 Hz.
  • H-3 (next to CHO): δ 7.25, dd, J_(3,4)≈3.6, J_(3,5)≈0.8 Hz.
  • H-4: δ 6.60, dd, J_(3,4)≈3.6, J_(4,5)≈1.7 Hz.

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

Introduction. Chemical shift tells the electronic environment of a proton, and spin–spin coupling (n+1 rule, coupling constant J in Hz) tells how many neighbouring protons it has and how they are related. In aromatic rings Jₒᵣₜₕₒ (7–9 Hz) ≫ Jₘₑₜₐ (1–3 Hz) > Jₚₐᵣₐ (<1 Hz).

(i) Furfural (furan-2-carbaldehyde)

Four signals. The ring protons form an AMX system; each is a doublet of doublets.

  • CHO: δ 9.65 (s; a small 0.8 Hz long-range coupling may be seen).
  • H-5 (next to O): δ 7.70, dd, J_(4,5)≈1.7, J_(3,5)≈0.8 Hz.
  • H-3 (next to CHO): δ 7.25, dd, J_(3,4)≈3.6, J_(3,5)≈0.8 Hz.
  • H-4: δ 6.60, dd, J_(3,4)≈3.6, J_(4,5)≈1.7 Hz.

Figure: H-3, H-4, H-5 on the ring.

In the furan ring J_(3,4) (≈3.6 Hz) is much larger than J_(4,5) (≈1.7 Hz): the 4,5-bond lies next to the electronegative ring oxygen, which lowers the coupling. Both are much smaller than benzene ortho couplings, because the five-membered ring has wider external angles. H-5 is most deshielded among ring H (adjacent to O); H-3 is deshielded by the C=O.

(ii)(A) Anthracene and phenanthrene

Anthracene (D₂ₕ) has only three kinds of H: H-9,10 δ 8.43 (singlet, 2H), H-1,4,5,8 δ 8.00 (m, 4H), H-2,3,6,7 δ 7.45 (m, 4H). Phenanthrene (C₂ᵥ) has five kinds: the bay protons H-4,5 at δ 8.70 (doublet, 2H, strongly deshielded by the facing ring), H-1,8 δ 7.90 (d), H-9,10 δ 7.75 (s), and H-2,3,6,7 δ 7.55–7.65 (m). So the lowest-field signal is a 2H singlet for anthracene, but a 2H doublet for phenanthrene, and the integrals divide 2: 4: 4 against 2: 2: 2: 4.

(ii)(B) Pure ethanol and ethanol with a trace of acid

In very pure, dry ethanol the OH proton exchanges slowly (lifetime on O longer than about 1/J). It couples with the CH₂: OH is a triplet (J≈5 Hz), CH₂ (δ 3.7) is a doublet of quartets (eight lines), CH₃ (δ 1.2) a triplet. A trace of acid (or base) catalyses rapid proton exchange; the spin of the OH proton is averaged, coupling to OH disappears, the OH becomes a sharp singlet and CH₂ a simple quartet.

(iii) 2- and 3-Nitroacetophenone

Scheme: Both have four ring H, arranged differently.

2-Nitroacetophenone3-Nitroacetophenone
Ring H patternfour adjacent H (H-3,4,5,6)H-2 isolated; H-4,5,6 adjacent
Ortho coupling gives2 doublets + 2 triplets1 singlet + 2 doublets + 1 triplet
Lowest-field ArHH-3 (ortho to NO₂) δ≈ 8.1, dH-2 δ≈ 8.75, singlet (between NO₂ and C=O)
Other ArHδ 7.75 (t), 7.65 (t), 7.45 (d)H-4 8.42 (d), H-6 8.29 (d), H-5 7.70 (t)
COCH₃δ≈ 2.55δ≈ 2.70

The low-field singlet near δ 8.75 marks the 3-isomer. In the 2-isomer the acetyl group is twisted out of the ring plane by the ortho nitro group, so the ring protons and the CH₃ are less deshielded by the C=O.

Conclusion. (i) Furfural: three dd ring signals with J_(3,4)≈3.6, J_(4,5)≈1.7, J_(3,5)≈0.8 Hz, and CHO at δ 9.65. (ii) Anthracene has three signals with a low-field singlet; phenanthrene five, with a low-field bay doublet. Pure ethanol shows an OH triplet; with acid the OH is a singlet and CH₂ a quartet. (iii) Only 3-nitroacetophenone shows an isolated low-field singlet (H-2).

Application. Proton-exchange decoupling is used to identify OH and NH signals (D₂O shake); coupling patterns of substituted benzenes are used routinely to assign isomers in drug impurity profiling.

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Model answer to Q8(b), 2026 Paper II: solution page 23
Solution page 23 of 26

All parts of Question 8