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UPSC Combined Geo-Scientist

Chemist

  • 3 descriptive papers
  • 200 marks each
  • 3 h per paper

Mains Paper I covers inorganic chemistry.

UPSC Combined Geo-Scientist, Mains · 2020 · Mains Paper I

Q1(i). Iodine beta decay

Question

₅₃¹³³ I is a beta emitter, while ₅₃¹²¹ I is a positron emitter. Explain.

Answer in brief

Iodine-133 is neutron rich and undergoes β⁻ decay; iodine-121 is proton rich and can lower its proton/neutron ratio through positron emission.

Key points

  • For ¹³³I, N=133-53=80. In β⁻ decay, n→ p+e⁻+ν̄ₑ: ¹³³₅₃I → ¹³³₅₄Xe+e⁻+ν̄ₑ.
  • For ¹²¹I, N=68. Positron emission converts p→ n+e⁺+νₑ: ¹²¹₅₃I → ¹²¹₅₂Te+e⁺+νₑ.
  • Both preserve mass number and move towards a more favourable neutron/proton balance. Electron capture can compete for proton-rich nuclei; energetics determines the allowed channels.

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(i), 2020 Mains Paper I: solution pages 5 and 6
Solution pages 5 and 6 of 16

CoversIodine beta decayNuclear stability