UPSC Combined Geo-Scientist, Mains · 2020 · Mains Paper I
Q1(i). Iodine beta decay
Question
₅₃¹³³ I is a beta emitter, while ₅₃¹²¹ I is a positron emitter. Explain.
Answer in brief
Iodine-133 is neutron rich and undergoes β⁻ decay; iodine-121 is proton rich and can lower its proton/neutron ratio through positron emission.
Key points
- For ¹³³I, N=133-53=80. In β⁻ decay, n→ p+e⁻+ν̄ₑ: ¹³³₅₃I → ¹³³₅₄Xe+e⁻+ν̄ₑ.
- For ¹²¹I, N=68. Positron emission converts p→ n+e⁺+νₑ: ¹²¹₅₃I → ¹²¹₅₂Te+e⁺+νₑ.
- Both preserve mass number and move towards a more favourable neutron/proton balance. Electron capture can compete for proton-rich nuclei; energetics determines the allowed channels.
The full model answer
As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

CoversIodine beta decayNuclear stability
All parts of Question 1
- 1(a) Normal and inverse spinels5 marks
- 1(b) Trans effect5 marks
- 1(c) Boric acid titration5 marks
- 1(d) Aluminium oxinate5 marks
- 1(e) Iodometry and iodimetry5 marks
- 1(f) Magnesium-assisted EDTA endpoint5 marks
- 1(g) Triiron dodecacarbonyl5 marks
- 1(h) Masking and demasking5 marks
- 1(i) Iodine beta decay5 marks
- 1(j) Transition elements and CuCl5 marks