UPSC Combined Geo-Scientist, Mains · 2020 · Mains Paper II
Q13(b). Numerical second-order rate constant
Question
For the preceding reaction, a=0.075 mol L⁻¹, b=0.050 mol L⁻¹ and [B]=0.020 mol L⁻¹ after 1 hour. Calculate k.
Answer in brief
k=16.22 L mol⁻¹ h⁻¹=4.505×10⁻³ L mol⁻¹ s⁻¹.
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CoversNumerical second-order rate constantChemical kinetics
All parts of Question 13
- 13(a) Unequal-concentration second-order kinetics10 marks
- 13(b) Numerical second-order rate constant10 marks