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UPSC Combined Geo-Scientist

Chemist

  • 3 descriptive papers
  • 200 marks each
  • 3 h per paper

Mains Paper II covers physical chemistry.

UPSC Combined Geo-Scientist, Mains · 2023 · Mains Paper II

Q1(e). Chemical potential and its link with Gibbs energy

Question

Explain the physical significance of chemical potential. How is it related to Gibbs free energy?

Answer in brief

μᵢ = (∂G/∂nᵢ)T,P,nⱼ, the partial molar Gibbs energy: the escaping tendency of species i. Matter moves from high μ to low μ. G = ∑nᵢμᵢ; pure substance μ = Gm.

Key points

  • Meaning: the change in G when 1 mol of i is added to a very large amount of the mixture at constant T, P and composition.
  • Escaping tendency: matter flows from high μ to low μ, as heat flows from high T to low T.
  • Equilibrium: μᵢ equal in every phase; ∑νᵢμᵢ = 0 for reaction equilibrium.
  • Relation to G: G = ∑nᵢμᵢ; for a pure substance μ = Gm.
  • (∂μ/∂T)P = −Sm, (∂μ/∂P)T = Vm, μᵢ = μᵢ° + RT ln aᵢ.

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(e), 2023 Mains Paper II: solution pages 5 and 6
Solution pages 5 and 6 of 36

Coverschemical potentialpartial molar Gibbs energyescaping tendencyGibbs free energyphase equilibrium