UPSC Combined Geo-Scientist, Mains · 2023 · Mains Paper II
Q6(a). Emf of a hydrogen-electrode concentration cell
Question
Calculate the potential of the following cell: Pt(H₂, 0.1 atm) | HCl (1 M) | Pt(H₂, 1 atm).
Answer in brief
E = −0.0296 V at 298 K. The cell as written is not spontaneous; reversed, it gives +0.0296 V.
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Coversconcentration cellhydrogen electrodeNernst equationelectrode concentration cellemf
All parts of Question 6
- 6(a) Emf of a hydrogen-electrode concentration cell5 marks
- 6(b) Types of reversible electrodes5 marks