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UPSC Combined Geo-Scientist

Chemist

  • 3 descriptive papers
  • 200 marks each
  • 3 h per paper

Mains Paper II covers physical chemistry.

UPSC Combined Geo-Scientist, Mains · 2026 · Mains Paper II

Q1(p). Non-radiative decay competing with fluorescence

  • 5 marks
  • Topic: Photochemistry
  • Answered
Question

An excited molecule can lose energy without emitting light. Name two non-radiative decay processes and explain one reason why these processes compete with fluorescence.

Answer in brief

Internal conversion (S₁→ S₀, same spin) and intersystem crossing (S₁→ T₁). They compete because they are first-order processes of similar rate, so Φ_f=k_f/(k_f+k_(IC)+k_(ISC)+k_q[Q])<1.

Key points

  • an isoenergetic radiationless step to a high vibrational level of a lower electronic state of the same multiplicity; fast when the vibrational overlap is large (small energy gap, flexible molecule).
  • a spin-forbidden change to the triplet state, helped by spin–orbit coupling (heavy atoms).
  • fluorescence rate k_f≈10⁷–10⁹ s⁻¹ is only slightly faster than k_(IC) and k_(ISC); all channels deplete S₁ in parallel, so the fluorescence quantum yield and lifetime τ=1/(k_f+k_(IC)+k_(ISC)) are reduced.

The full model answer

Worked out step by step, as it should go in the answer booklet. The solution sheet follows it.

  • Internal conversion: an isoenergetic radiationless step to a high vibrational level of a lower electronic state of the same multiplicity; fast when the vibrational overlap is large (small energy gap, flexible molecule).
  • Intersystem crossing: a spin-forbidden change to the triplet state, helped by spin–orbit coupling (heavy atoms).
  • Why they compete: fluorescence rate k_f≈10⁷–10⁹ s⁻¹ is only slightly faster than k_(IC) and k_(ISC); all channels deplete S₁ in parallel, so the fluorescence quantum yield and lifetime τ=1/(k_f+k_(IC)+k_(ISC)) are reduced.
Model answer to Q1(p), 2026 Mains Paper II: solution page 11
Solution page 11 of 22

Coversdecay of excited statesNon-radiative decay competing with fluorescence