Q10(a). Chlorinated allylic structure
IR 3030,1510,1380,930 cm⁻¹; MS 210(10%),208(30%),173(50%),57(100%). ¹H: 7.2–7.4(m,5H),6.5(d,J=20,1H),6.3(dd,J=20,6,1H),4.3(d,J=6,1H),1.2(s,9H). ¹³C:28,37,74,126,127,128,129,132,135. Deduce structure.
Answer in brief
(E)-PhCH=CHCH(Cl)C(CH₃)₃, 3-chloro-4,4-dimethyl-1-phenylpent-1-ene.
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CoversChlorinated allylic structureCombined spectral analysis
All parts of Question 10
- 10(a) Chlorinated allylic structure10 marks
- 10(b) Acetylacetone proton NMR5 marks
- 10(c) Activated Hofmann elimination5 marks
- 10(d) Frost circles and aromaticity10 marks