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UPSC Combined Geo-Scientist

Chemist

  • 3 descriptive papers
  • 200 marks each
  • 3 h per paper

Mains Paper III covers analytical and organic chemistry.

UPSC Combined Geo-Scientist, Mains · 2022 · Mains Paper III

Q4(a). Absorbance of an unbuffered indicator solution at 430 nm

Question

The equilibrium constant for the given conjugate acid–base pair is 2.5 × 10⁻⁵: HIn + H₂O ⇌ In⁻ + H₃O⁺. Determine the absorbance at 430 nm for the concentration of HIn = 3.0 × 10⁻⁴ M (up to 3 decimal places), using the following data: HIn, absorption maximum 430 nm, molar absorptivity 4.0 × 10³ at 430 nm and 7.25 × 10² at 600 nm; In⁻, absorption maximum 600 nm, molar absorptivity 3.0 × 10² at 430 nm and 9.65 × 10³ at 600 nm. Given: path length of the cuvette = 1 cm; molar absorptivity in M⁻¹ cm⁻¹.

Answer in brief

A₄₃₀ = 0.923 (exact 0.9225). Without a buffer 25 % of the indicator is ionised: [HIn] = 2.25 × 10⁻⁴ M and [In⁻] = 7.5 × 10⁻⁵ M.

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CoversBeer's lawadditivity of absorbanceindicator absorbancechemical deviationmolar absorptivity

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