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UPSC Combined Geo-Scientist

Chemist

  • 3 descriptive papers
  • 200 marks each
  • 3 h per paper

Mains Paper III covers analytical and organic chemistry.

UPSC Combined Geo-Scientist, Mains · 2024 · Mains Paper III

Q1(a). Percentage relative error of a balance reading

Question

A weighing balance showed the weight of a substance 9.5 g, which is 0.5 g lower than its actual weight. Calculate % relative error.

Answer in brief

True mass = 10.0 g; relative error = (9.5 − 10.0)/10.0 × 100 = −5.0 %, so the balance reads 5 % low.

Key points

  • True (actual) mass: xt = 9.5 + 0.5 = 10.0 g.
  • Absolute error = measured value − true value, with its sign: E = 9.5 − 10.0 = −0.5 g.
  • Relative error = absolute error as a percentage of the true value: Er = −0.5/10.0 × 100 = −5.0 % (−50 parts per thousand).
  • The negative sign is kept: the result is lower than the true value; relative accuracy = 95 %.
  • A balance that reads low is a determinate (systematic) error; it is removed by calibration with standard masses.

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(a), 2024 Mains Paper III: solution pages 1 and 2
Solution pages 1 and 2 of 41

Coversrelative errorabsolute errordeterminate erroraccuracycalibration