QuestionAtomic structure / nodes
The number of radial nodes for 2s, 3p and 3d orbitals, respectively are:
- (a) 2, 1, 0
- (b) 2, 1, 1
- (c) 1, 0, 0
- (d) 1, 1, 0
Answer: (d) 1, 1, 0
Radial nodes = n − l − 1. 2s: 2 − 0 − 1 = 1. 3p: 3 − 1 − 1 = 1. 3d: 3 − 2 − 1 = 0. So 1, 1, 0 → (d). Remember: angular nodes = l; total nodes = n − 1.