QuestionChemical equilibrium / van 't Hoff equation
The variation of log₁₀K with 1/T is shown in the following graph in which the straight line is at 45° (where K is the equilibrium constant, R = 8·3 J K⁻¹ mol⁻¹; tan 45° = 1; ln 10 = 2·303) :
The value of ΔH° is approximately
- (a) +19·1 J mol⁻¹
- (b) −19·1 J mol⁻¹
- (c) +8·3 J mol⁻¹
- (d) −8·3 J mol⁻¹
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