QuestionElectrochemistry / conductance at equivalence
During the titration of 50·0 mL of a 0·10 mol L⁻¹ solution of acetic acid (Kₐ = 1·8×10⁻⁵) with a 0·10 mol L⁻¹ solution of sodium hydroxide, the specific conductance after addition of 50·0 mL of sodium hydroxide will be : (Given : \(\lambda^o_{CH_3COO^-}\) = 40·9×10⁻⁴ S m²mol⁻¹, \(\lambda^o_{Na^+}\) = 50·1×10⁻⁴ S m²mol⁻¹)
- (a) 0·455 S m⁻¹
- (b) 0·910 mS m⁻¹
- (c) 0·455 mS m⁻¹
- (d) 0·910 S m⁻¹
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