QuestionPhysics / current electricity
A metallic wire having length l and area of cross-section A has a resistance R. It is now connected in series with a wire of same metal but with length 2l and area of cross-section 2A. The total resistance of the combination will be:
- (a) 2R
- (b) 4R
- (c) R
- (d) R/2
Answer: (a) 2R
R = ρl/A. Second wire: ρ(2l)/(2A) = R. In series: R + R = 2R → (a).