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VKC Notes · Surface chemistry · Civil Services P-I · IFoS P-I · Geo-Scientist P-II

11.2 Adsorption, Heterogeneous Catalysis and Colloids

★★★ 2021–2025: 25 parts, 218 marks (Civil Services 9 parts / 100 m · IFoS 6 / 61 m · Geo-Scientist 10 / 57 m). The Langmuir derivation has been set as a 15–20-mark question three times.

Syllabus lines. Civil Services and IFoS: “Adsorption from gases and solutions on solid adsorbents; Langmuir and B.E.T. adsorption isotherms; determination of surface area, characteristics and mechanism of reaction on heterogeneous catalysts”. Geo-Scientist: “Physisorption and chemisorption, adsorption isotherms, Freundlich and Langmuir adsorption isotherms, BET equation, surface area determination; colloids, electrical double layer and colloid stability, electrokinetic phenomenon. Elementary ideas about soaps and detergents, micelles, emulsions”.

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CSE 2024 Q7(a) = asked there; tap to open the solved answerSN = line kept in the short notes

11.2.1 Physisorption and chemisorption ★★

PhysisorptionChemisorption
Forcevan der Waalschemical bond to surface atoms
|ΔHads|20–40 kJ mol⁻¹ (≈ heat of liquefaction)80–400 kJ mol⁻¹
Activation energynoneoften present (activated adsorption)
Layersmultilayer possiblemonolayer only
Specificityany gas, more for easily liquefied onesspecific to gas–surface pair
With rising Tfalls steadilyrises, then falls (isobar has a maximum)
  • Temperature: physisorption needs no activation and is exothermic, so heating only drives gas off. Chemisorption first needs its activation energy (rate ∝ e−Ea/RT), so uptake rises with T until equilibrium is reached; beyond that, being exothermic, it falls Geo 2024 Q5(b) 5m.SN
  • Entropy: a gas molecule held on a surface loses translational freedom, so ΔSads < 0. Since adsorption is spontaneous (ΔG < 0), ΔH = ΔG + TΔS must be negative: adsorption is exothermic. The statement “adsorption increases entropy” is wrong for the adsorbate; it can hold only for the whole system in special cases (water released from a surface when a solute adsorbs from solution, dissociative adsorption) Geo 2023 Q9(c) 2m.SN
  • Finely divided adsorbents: adsorption is a surface effect, x/m ∝ specific area. A 1 cm cube (6 cm²) cut into 1 µm cubes gives 10¹² cubes, 6 m²: 10⁴ times the area, plus more edges, corners and defects (active sites). Activated charcoal 500–1500 m² g⁻¹ Geo 2021 Q1(g) 5m.SN
  • Water on glass: glass below the dew point; its Si–OH groups hydrogen-bond water, so a flat nucleus forms at very small supersaturation (heterogeneous nucleation; a free tiny droplet would need much more, Kelvin equation) and spreads into a film; greasy glass gives droplets (fogging) CSE 2024 Q5(b)(i) 5m.

11.2.2 Langmuir adsorption isotherm ★★★ asked every year

Assumptions Geo 2024 Q7(a) 5m:SN

  1. A fixed number of equivalent sites; each holds one molecule; adsorption stops at a monolayer.
  2. No interaction between adsorbed molecules, so ΔHads does not depend on θ.
  3. Dynamic equilibrium: rate of adsorption = rate of desorption.

Derivation. Let θ = fraction of sites covered.

(11.2.1)
(11.2.2)
(11.2.3)
θ = 1θ ≈ Kp(first order)θ → 1 (zero order)pθslope = 1/Vₘintercept = 1/(KVₘ)pp/V
Fig. 11.2.1 Langmuir isotherm and its linear plot.
Draw it in 60 s: left: a curve rising straight from the origin and bending flat under a dashed line θ = 1; right: a straight line, intercept 1/KVₘ, slope 1/Vₘ.
  • Low p (Kp ≪ 1): θ = Kp, amount ∝ p¹, “first order”. High p (Kp ≫ 1): θ → 1, amount ∝ p⁰, “zero order”: the monolayer is full CSE 2021 Q6(c) 20m CSE 2025 Q6(c) 20m IFoS 2025 Q5(b) 8m IFoS 2022 Q5(b) 8m.SN
  • Where it fails: at high p real isotherms keep rising (multilayers, type II); real surfaces have sites of different energy and ΔHads falls with θ; adsorbed molecules do interact. The Langmuir isotherm holds at low p and for chemisorption best.SN
  • Dissociative adsorption (H₂ → 2H on a metal): θ = (Kp)½/(1 + (Kp)½).

Solved PYQ Geo 2025 Q12(c) 5m

Langmuir isotherm with K = 0.75 kPa⁻¹ at 298 K. Pressure for θ = 0.15 and 0.95?

  1. Rearrange (11.2.2): p = θ/[K(1 − θ)].
  2. θ = 0.15: p = 0.15/(0.75 × 0.85) = 0.235 kPa; θ = 0.95: p = 0.95/(0.75 × 0.05) = 25.3 kPa.
  3. Coverage rises about 6 times but pressure about 108 times: the last sites fill slowly (saturation).SN

11.2.3 Freundlich isotherm ★★

(11.2.4)
  • Empirical; a log–log plot is a straight line of slope 1/n, intercept log k. Works at intermediate pressures and for adsorption from solution (concentration c for p); fails at high p (no saturation) IFoS 2023 Q6(c) 10m.SN
  • From Langmuir: at intermediate p, θ = Kp/(1 + Kp) varies between p¹ and p⁰, so it behaves as p1/n with 0 < 1/n < 1. Theory: Freundlich is exact for a surface whose sites have an exponential spread of adsorption energies IFoS 2021 Q7(a) 15m.SN
  • Five features of a catalyst: gives a new path of lower Ea; unchanged at the end; small amounts suffice; often specific; does not change ΔG° or K (speeds forward and back equally) IFoS 2023 Q6(c).

11.2.4 BET isotherm and the five isotherm types ★★★

Type IType IIType IIIType IVType Vx-axis: p/p° (0 → 1) · y-axis: amount adsorbedI Langmuir (monolayer, micropores) · II, IV multilayer (BET; IV with capillary condensation) · III, V weak first layer
Fig. 11.2.2 The five types of adsorption isotherm (Brunauer).
Draw it in 60 s: five small axes side by side: I flattens; II flattens then turns up; III curves up from the start; IV like II but flattens again near p°; V like III with a plateau.
(11.2.5)
  • Terms: p = equilibrium pressure; p° = saturation vapour pressure of the adsorbate; V = volume adsorbed (STP); Vm = volume for one complete monolayer; c ≈ e(ΔH₁ − ΔHL)/RT, set by the heat of adsorption of the first layer over the heat of liquefaction Geo 2024 Q1(h) 5m Geo 2022 Q14(a) 10m.SN
  • Model: Langmuir's ideas applied layer by layer; the first layer is held by the surface, the second and higher layers like a liquid; when only one layer can form it reduces to Langmuir. Large c gives type II, small c (weak first layer) type III; pores add capillary condensation (IV, V) IFoS 2022 Q7(a) 10m.SN
  • Surface area by BET: measure N₂ uptake at 77 K for p/p° ≈ 0.05–0.30; plot p/[V(p° − p)] against p/p°: slope s, intercept i, so Vm = 1/(s + i), c = 1 + s/i. Then area per gram IFoS 2024 Q4(c) 10m:SN
(11.2.6)

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