UPSC Civil Services (Mains), Chemistry optional · 2025 · Paper I
Q1(e). Superheating of liquids and the Kelvin equation
Question
Why do liquids become superheated before boiling? Explain using Kelvin equation.
Answer in brief
A newly formed bubble is so small that the vapour inside it cannot hold it open at Tb, so the liquid overshoots Tb.
Key points
- Boiling needs bubbles of vapour to form inside the liquid and then grow.
- Kelvin equation for a cavity of radius r: p = p* exp(−2γVm/rRT); the vapour pressure inside a cavity is below p* and falls further as r gets smaller.
- To stay open the bubble must also balance surface tension (Laplace): pin = pext + 2γ/r; for water a bubble of r = 1 μm needs 2.2 atm inside.
- At Tb, p* only equals pext, so a tiny bubble collapses; the liquid must be heated above Tb (superheating), and boiling chips supply large cavities to prevent bumping.
The full model answer
As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

CoversKelvin equationsuperheatingLaplace pressuresurface tensionbumpingvapour pressure of curved surface
All parts of Question 1
- 1(a) Probability of the 1s electron at a₀ and at 10a₀5 marks
- 1(b) Born–Haber cycle for NaCl at 298 K5 marks
- 1(c) Raising the conductivity of Ge and Si by trace elements5 marks
- 1(d) Heat conduction between two copper sheets through air5 marks
- 1(e) Superheating of liquids and the Kelvin equation5 marks
- 1(f) Ascending order of dipole moment: NH₃, NF₃, H₂O5 marks
- 1(g) Heat of combustion of naphthalene from bomb calorimetry5 marks
- 1(h) Sealed sample: ethane, neon or a mixture5 marks
- 1(i) Time to plate a gold layer5 marks
- 1(j) Maximum work of a steam turbine5 marks