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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper I covers physical and inorganic chemistry.

UPSC Civil Services (Mains), Chemistry optional · 2025 · Paper I

Q1(j). Maximum work of a steam turbine

Question

A steam turbine is operated with an intake temperature of 400 °C, and an exhaust temperature of 150 °C. What is the maximum amount of work the turbine can do for a given heat input ‘Q’? Under what conditions is the maximum work achieved?

Answer in brief

wmax = 0.371 Q (37.1 % of the heat taken in), reached only when every step is reversible.

Key points

  • The second law does not allow all of Q to become work; the largest work comes from a reversible (Carnot) engine between the same two temperatures.
  • η = wmax/Q = 1 − Tc/Th = 1 − 423 K/673 K = 0.371, so wmax = 0.371 Q and 0.629 Q must leave at 150 °C.
  • Conditions: heat taken in isothermally at 673 K and rejected isothermally at 423 K, with frictionless adiabatic expansion and compression in between, so that ΔSuniv = 0.
  • A real turbine gives less, because friction and heat flow across a finite temperature difference create entropy.

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(j), 2025 Paper I: solution pages 9 and 10
Solution pages 9 and 10 of 49

CoversCarnot cycleCarnot efficiencysecond law of thermodynamicsheat enginereversible process