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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper I covers physical and inorganic chemistry.

UPSC Civil Services (Mains), Chemistry optional · 2025 · Paper I

Q1(g). Heat of combustion of naphthalene from bomb calorimetry

Question

0.500 g of benzoic acid was burnt under oxygen. The combustion produced a temperature rise of 1.236 K. The same calorimetric set-up was used to burn 0.300 g of naphthalene and the resulting temperature rise was 1.128 K. The heat of combustion of benzoic acid, ΔcU298 = −3227 kJ mol⁻¹. What is the heat of combustion of naphthalene?

Answer in brief

ΔcU(naphthalene) = −5.15 × 10³ kJ mol⁻¹.

Key points

  • A bomb calorimeter works at constant volume, so the heat released equals ΔU; benzoic acid calibrates the set-up.
  • n(C₇H₆O₂) = 0.500/122.12 = 4.094 × 10⁻³ mol; heat released = 13.21 kJ; calorimeter constant C = 13.21/1.236 = 10.69 kJ K⁻¹.
  • Heat released by naphthalene = 10.69 × 1.128 = 12.06 kJ; n(C₁₀H₈) = 0.300/128.17 = 2.341 × 10⁻³ mol.
  • ΔcU = −12.06/2.341 × 10⁻³ = −5152 kJ mol⁻¹; with Δng = −2, ΔcH = ΔcU − 2RT = −5157 kJ mol⁻¹.

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(g), 2025 Paper I: solution pages 7 and 8
Solution pages 7 and 8 of 49

Coversbomb calorimetercalorimeter constantheat of combustionbenzoic acid calibrationΔU and ΔHnaphthalene