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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper II covers organic chemistry and spectroscopy.

UPSC Civil Services (Mains), Chemistry optional · 2018 · Paper II

Q1(b). NBS: preparation and allylic bromination of propene

  • 10 marks
  • Answered
Question

How is NBS obtained from succinimide? Write its reaction with propene in presence of sunlight. Outline the mechanism.

Answer in brief

NBS is made from succinimide with Br₂ in cold aqueous NaOH. With propene in sunlight it gives 3-bromopropene (allyl bromide) by a radical chain through the resonance-stabilised allyl radical; NBS keeps Br₂ low and so suppresses addition.

Key points

  • light breaks the weak N–Br bond (or a trace of Br₂): Br₂ →2 Br•
  • Br• abstracts an allylic H from the CH₃ group. The allylic C–H is the weakest C–H in propene, because the allyl radical is resonance-stabilised: CH₂=CH-CH₂• <→ •CH₂-CH=CH₂.
  • the allyl radical takes Br from Br₂: CH₂=CH-CH₂• + Br₂ → CH₂=CH-CH₂Br + Br•
  • the HBr formed in step 2 reacts with NBS (ionic) to give succinimide and Br₂: NBS + HBr → succinimide + Br₂. So Br₂ is regenerated continuously but only at a low concentration.

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

Introduction. N-Bromosuccinimide (NBS) is the standard reagent for allylic bromination (Wohl–Ziegler reaction). It supplies bromine radicals while holding the concentration of Br₂ very low, so substitution at the allylic C–H wins over addition to the C=C.

Preparation of NBS

Succinimide (the N–H is acidic, flanked by two C=O) is dissolved in cold aqueous NaOH (ice bath, 0–5°C) and bromine is added. The imide anion takes Br⁺ from Br₂; NBS precipitates and is filtered off.

Scheme: Succinimide → N-bromosuccinimide.

Reaction with propene

Scheme: Allylic substitution: the C=C is kept.

Mechanism: radical chain

  1. Initiation: light breaks the weak N–Br bond (or a trace of Br₂): Br₂ →2 Br•
  2. Propagation 1: Br• abstracts an allylic H from the CH₃ group. The allylic C–H is the weakest C–H in propene, because the allyl radical is resonance-stabilised: CH₂=CH-CH₂• <→ •CH₂-CH=CH₂.
  3. Propagation 2: the allyl radical takes Br from Br₂: CH₂=CH-CH₂• + Br₂ → CH₂=CH-CH₂Br + Br•
  4. Role of NBS: the HBr formed in step 2 reacts with NBS (ionic) to give succinimide and Br₂: NBS + HBr → succinimide + Br₂. So Br₂ is regenerated continuously but only at a low concentration.
  5. Why no addition: addition of Br• to the C=C is reversible, and capture of the adduct radical needs Br₂; at very low [Br₂] the radical loses Br again, while allylic H abstraction is irreversible. Termination: two radicals combine.

Conclusion. NBS is made from succinimide with Br₂ in cold aqueous NaOH. With propene in sunlight it gives 3-bromopropene (allyl bromide) by a radical chain through the resonance-stabilised allyl radical; NBS keeps Br₂ low and so suppresses addition.

Application. NBS allylic bromination is used to make allylic bromides for synthesis (e.g. 3-bromocyclohexene), and the same reagent in aqueous DMSO gives bromohydrins.

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Model answer to Q1(b), 2018 Paper II: solution page 3
Solution page 3 of 24