Q1(c). Squaric acid; acylation of trans-2-butene
(i) Account for the fact that compound A is almost as strong an acid as H₂SO₄:
[A]
(ii) What happens when trans-2-butene is reacted with CH₃COCl in presence of anhydrous AlCl₃?
Answer in brief
(i) Squaric acid is very strong because its mono- and di-anions are fully delocalised and the dianion is a 2π aromatic, symmetric ring (pK₁ ≈ 1.5). (ii) trans-2-Butene is acylated: the acylium ion adds to give 4-chloro-3-methylpentan-2-one, which loses HCl to the conjugated enone 3-methylpent-3-en-2-one.
Key points
- O=C–C=C–OH. The charge of the anion is delocalised over the C=O through the ring C=C.
- After both protons are lost, the dianion C₄O₄²⁻ has D₄ₕ symmetry: all four C–C and all four C–O bonds are equal, and each O carries half a negative charge.
- The four-membered ring then holds 2π electrons (Hückel 4n+2, n=0): the ring is aromatic, like the cyclopropenyl cation.
- The sp² ring carbons and the electron-withdrawing C=O groups also stabilise the anion inductively.
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
Introduction. (i) A is squaric acid, 3,4-dihydroxycyclobut-3-ene-1,2-dione. Its strength comes from the stability of its anions. (ii) is a Friedel–Crafts acylation of an alkene (Darzens–Nenitzescu reaction).
(i) Squaric acid
- The O–H is a vinylogous carboxylic acid: O=C–C=C–OH. The charge of the anion is delocalised over the C=O through the ring C=C.
- After both protons are lost, the dianion C₄O₄²⁻ has D₄ₕ symmetry: all four C–C and all four C–O bonds are equal, and each O carries half a negative charge.
- The four-membered ring then holds 2π electrons (Hückel 4n+2, n=0): the ring is aromatic, like the cyclopropenyl cation.
Figure: Squarate dianion: four equal C–O bonds, each O about -12; 2π aromatic ring.
- The sp² ring carbons and the electron-withdrawing C=O groups also stabilise the anion inductively.
- Result: pK₁ is about 1.5 and pK₂ about 3.5 (March): even the second proton is lost more easily than the proton of acetic acid (pKₐ 4.76). In water the first ionisation is nearly complete, which is why A is called almost as strong as H₂SO₄.
(ii) trans-2-Butene and CH₃COCl/AlCl₃
- AlCl₃ takes Cl⁻ from acetyl chloride: acylium ion CH₃C#O⁺ (AlCl₄⁻ counter-ion).
- The C=C attacks the acylium carbon: a secondary carbocation β to the new C=O.
- The cation is trapped by Cl⁻ (from AlCl₄⁻): 4-chloro-3-methylpentan-2-one (two new stereocentres, mixture of diastereomers, racemic).
- On warming or on distillation (or with a base) HCl is eliminated: the C=C forms in conjugation with C=O, giving the α,β-unsaturated ketone 3-methylpent-3-en-2-one. Direct loss of H⁺ from the cation gives the same enone and some β,γ-isomer.
Scheme: Electrophilic addition of the acylium ion, then loss of HCl.
Conclusion. (i) Squaric acid is very strong because its mono- and di-anions are fully delocalised and the dianion is a 2π aromatic, symmetric ring (pK₁ ≈ 1.5). (ii) trans-2-Butene is acylated: the acylium ion adds to give 4-chloro-3-methylpentan-2-one, which loses HCl to the conjugated enone 3-methylpent-3-en-2-one.
Application. Squaric acid is the starting material for squaraine dyes (near-infrared absorbers used in imaging and solar cells); aliphatic Friedel–Crafts acylation of alkenes is a direct route to α,β-unsaturated ketones.
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All parts of Question 1
- 1(a) π-MO energy levels: benzene, cyclobutadiene, cyclopentadienyl anion10 marks
- 1(b) NBS: preparation and allylic bromination of propene10 marks
- 1(c) Squaric acid; acylation of trans-2-butene10 marks
- 1(d) Thermal [1,3]- and [1,5]-hydrogen shifts10 marks
- 1(e) Photochemical [2+2] cycloaddition of methyl vinyl ketone and ethene10 marks