Q1(d). Thermal [1,3]- and [1,5]-hydrogen shifts
Which of the following known sigmatropic rearrangements would proceed readily and which slowly? Explain your answers:
(i) CH₃-CH=CD₂ → CH₂=CH-CHD₂
(ii) [structure] → [structure]
Answer in brief
(i) The [1,3]-H shift is suprafacially forbidden and antarafacially impossible: it proceeds slowly. (ii) The [1,5]-H shift is suprafacially allowed (six electrons): it proceeds readily.
Key points
- H moves from C-3 (CH₃) to C-1 (CD₂) across a three-carbon allyl unit: a [1,3] shift, 4 electrons (one σ bond + one π bond).
- The HOMO of the allyl radical, ψ₂, has a node at C-2 and opposite phases at C-1 and C-3 on the same face. A suprafacial shift would need H to bond to both ends with the same lobe: symmetry-forbidden.
- The allowed path, antarafacial, would need H to reach from the top face of C-3 to the bottom face of C-1: impossible for a three-atom chain.
- So the thermal reaction is very slow; the label scrambles only at high temperature by non-concerted (radical) routes, or under irradiation (photochemical [1,3] shifts are suprafacially allowed).
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
Reading of the question: the product of (i) is printed as CH₂=CH-CD₂ with an H on the last carbon, i.e. CH₂=CH-CHD₂.
Introduction. A thermal sigmatropic shift of hydrogen is analysed as a hydrogen atom (1s orbital) moving across the HOMO of the radical left behind. H has only one lobe, so it can only move suprafacially (on one face); an antarafacial path for H across a short chain is geometrically impossible. Woodward–Hoffmann: a thermal suprafacial [1,j]-H shift is allowed when j+1 = 4n+2.
Figure: Shaded and open lobes are opposite phases. H bridges the two ends on the top face only.
(i) [1,3]-H shift in 1,1-dideuteriopropene: slow
- H moves from C-3 (CH₃) to C-1 (CD₂) across a three-carbon allyl unit: a [1,3] shift, 4 electrons (one σ bond + one π bond).
- The HOMO of the allyl radical, ψ₂, has a node at C-2 and opposite phases at C-1 and C-3 on the same face. A suprafacial shift would need H to bond to both ends with the same lobe: symmetry-forbidden.
- The allowed path, antarafacial, would need H to reach from the top face of C-3 to the bottom face of C-1: impossible for a three-atom chain.
- So the thermal reaction is very slow; the label scrambles only at high temperature by non-concerted (radical) routes, or under irradiation (photochemical [1,3] shifts are suprafacially allowed).
(ii) [1,5]-H shift in 7-deuteriocycloheptatriene: ready
- The C-7 hydrogen moves to C-4, five atoms away round the triene (C7→C1→C2→C3→C4): a [1,5] shift, 6 electrons. C-4 becomes the new CH₂; C-7 becomes sp² and keeps D, as printed.
- The pentadienyl HOMO, ψ₃, has the same phase at C-1 and C-5 on the same face, so a suprafacial shift is thermally allowed (aromatic, six-electron Hückel transition state).
- The ring holds the two termini close; the shift goes at moderate temperatures (around 100°C) and repeated shifts walk the label round the ring.
- H rather than D migrates in the printed product, as the primary kinetic isotope effect (C–H is easier to break than C–D) predicts.
Conclusion. (i) The [1,3]-H shift is suprafacially forbidden and antarafacially impossible: it proceeds slowly. (ii) The [1,5]-H shift is suprafacially allowed (six electrons): it proceeds readily.
Application. Thermal [1,5]-H shifts scramble substituents in cyclopentadienes and cycloheptatrienes and are the step that converts previtamin D into vitamin D (an antarafacial [1,7]-H shift in that open chain).
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All parts of Question 1
- 1(a) π-MO energy levels: benzene, cyclobutadiene, cyclopentadienyl anion10 marks
- 1(b) NBS: preparation and allylic bromination of propene10 marks
- 1(c) Squaric acid; acylation of trans-2-butene10 marks
- 1(d) Thermal [1,3]- and [1,5]-hydrogen shifts10 marks
- 1(e) Photochemical [2+2] cycloaddition of methyl vinyl ketone and ethene10 marks