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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper II covers organic chemistry and spectroscopy.

UPSC Civil Services (Mains), Chemistry optional · 2019 · Paper II

Q4(b). 'Etard reaction, Clemmensen reduction, Michael addition

  • 15 marks
  • Answered
Question

Write the name of the reaction and reagent required for the following conversions:
(i) [structure] → [structure]
(ii) [structure] → [structure]
(iii) [structure] + MVK → [structure]

Answer in brief

(i) 'Etard reaction, CrO₂Cl₂/CS₂ then H₂O; (ii) Clemmensen reduction, Zn(Hg)/conc. HCl; (iii) Michael addition, base (NaOEt) or pyrrolidine enamine (Stork) followed by H₃O⁺.

Key points

  • Introduction. (i) is a controlled oxidation of a benzylic CH₃ to CHO, (ii) the reduction of an aryl ketone C=O to CH₂ with an ester present, (iii) the 1,4-addition of a ketone enolate (or enamine) to methyl vinyl ketone.
  • Scheme: The 'Etard complex is hydrolysed to the aldehyde; over-oxidation is avoided.

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

Introduction. (i) is a controlled oxidation of a benzylic CH₃ to CHO, (ii) the reduction of an aryl ketone C=O to CH₂ with an ester present, (iii) the 1,4-addition of a ketone enolate (or enamine) to methyl vinyl ketone.

(i) Toluene to benzaldehyde: 'Etard reaction

Scheme: The 'Etard complex is hydrolysed to the aldehyde; over-oxidation is avoided.

Reagent: chromyl chloride, CrO₂Cl₂, in CS₂ (or CCl₄), then water. Chromyl chloride abstracts benzylic H and forms a brown insoluble 'Etard complex, C₆H₅CH(OCrOHCl₂)₂; hydrolysis gives benzaldehyde. Because the complex precipitates, the aldehyde is not oxidised further to benzoic acid. (Alternative: CrO₃ in acetic anhydride gives benzylidene diacetate, which is hydrolysed to benzaldehyde.)

(ii) Aryl ketone to CH₂: Clemmensen reduction

Scheme: Only the ketone C=O is reduced; the aromatic ring and the ester survive.

Reagent: zinc amalgam and concentrated HCl (Clemmensen reduction). Electrons transfer from the zinc surface to the protonated carbonyl (zinc carbenoid/organozinc intermediates, not the alcohol), and the C=O becomes CH₂. Aryl ketones are reduced especially well. The ethyl ester largely survives the acidic medium (any acid formed can be re-esterified); the Wolff–Kishner reduction, NH₂NH₂/KOH, would hydrolyse the ester completely. Hydrogenolysis with H₂, Pd/C in acid is an alternative for benzylic ketones.

(iii) Cyclohexanone + MVK: Michael addition

Scheme: Stork enamine version of the Michael reaction.

Name: Michael addition (conjugate, 1,4-addition) of the ketone's α-carbon to the β-carbon of methyl vinyl ketone. Reagent: a base such as NaOEt in EtOH or catalytic KOH (enolate as Michael donor), or better the Stork enamine method: pyrrolidine forms the enamine, which adds to MVK, and aqueous acid hydrolyses the iminium back to the ketone. Mild conditions stop the reaction at the 1,5-diketone; with strong base and heat this diketone would go on to an intramolecular aldol (Robinson annulation) to give octalone.

Conclusion. (i) 'Etard reaction, CrO₂Cl₂/CS₂ then H₂O; (ii) Clemmensen reduction, Zn(Hg)/conc. HCl; (iii) Michael addition, base (NaOEt) or pyrrolidine enamine (Stork) followed by H₃O⁺.

Application. The ketone of (ii) is the Friedel–Crafts succinoylation product of anisole; Clemmensen reduction and ring closure is the Haworth route to tetralones and naphthalenes, and the Michael product of (iii) is the Robinson-annulation precursor of octalone, the classic ring-building step of steroid synthesis.

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Model answer to Q4(b), 2019 Paper II: book edition page 16
Book edition, page 16
Model answer to Q4(b), 2019 Paper II: book edition page 17
Book edition, page 17