Q4(c)(ii). Reimer–Tiemann reaction of p-cresol: normal and abnormal products
p-methylphenol on reaction with OH⁻/CHCl₃ gives two products. Write the structure of both and propose a suitable mechanism.
Answer in brief
The normal Reimer–Tiemann product is 2-hydroxy-5-methylbenzaldehyde (ortho formylation via:CCl₂); the abnormal product is 4-(dichloromethyl)-4-methylcyclohexa-2,5-dienone, formed by attack at the methyl-bearing para carbon.
Key points
- Ortho attack (normal product). The phenoxide attacks:CCl₂ through its ortho carbon, giving a -CCl₂⁻ carbanion on a cyclohexadienone. Proton transfer restores the aromatic ring: an o-(dichloromethyl)phenoxide.
- The benzal chloride is hydrolysed by OH⁻ (two SN steps via a quinone methide) to the aldehyde; acidification gives 2-hydroxy-5-methylbenzaldehyde (major).
- Para attack (abnormal product). Attack at C-4, which carries CH₃, gives a dienone with a quaternary carbon. There is no H on C-4 to lose, so aromaticity cannot be restored, and the CHCl₂ group, attached to an sp3 carbon,…
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
Introduction. CHCl₃ and OH⁻ generate dichlorocarbene (:CCl₂), an electrophile that attacks the electron-rich ring of the phenoxide (Reimer–Tiemann reaction). With p-cresol the para position is blocked by CH₃, so attack at the ortho carbon gives the normal aldehyde, while attack at the substituted para carbon gives a dienone that cannot re-aromatise.
CHCl₃ + OH⁻ ⇌ CCl₃⁻ + H₂O CCl₃⁻:CCl₂ + Cl⁻ (α-elimination)
Scheme: Normal (ortho-formyl) product and abnormal (4-dichloromethyl dienone) product.
- Ortho attack (normal product). The phenoxide attacks:CCl₂ through its ortho carbon, giving a -CCl₂⁻ carbanion on a cyclohexadienone. Proton transfer restores the aromatic ring: an o-(dichloromethyl)phenoxide.
- The benzal chloride is hydrolysed by OH⁻ (two SN steps via a quinone methide) to the aldehyde; acidification gives 2-hydroxy-5-methylbenzaldehyde (major).
- Para attack (abnormal product). Attack at C-4, which carries CH₃, gives a dienone with a quaternary carbon. There is no H on C-4 to lose, so aromaticity cannot be restored, and the CHCl₂ group, attached to an sp3 carbon, resists hydrolysis: 4-(dichloromethyl)-4-methylcyclohexa-2,5-dien-1-one (minor).
Conclusion. The normal Reimer–Tiemann product is 2-hydroxy-5-methylbenzaldehyde (ortho formylation via:CCl₂); the abnormal product is 4-(dichloromethyl)-4-methylcyclohexa-2,5-dienone, formed by attack at the methyl-bearing para carbon.
Application. The Reimer–Tiemann reaction makes salicylaldehyde (for coumarin) and vanillin-type aldehydes; the abnormal dienones are the classical evidence for the carbene mechanism.
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All parts of Question 4
- 4(a) Sydnone and imidazole; imidazolium and imidazolide ions15 marks
- 4(b) 'Etard reaction, Clemmensen reduction, Michael addition15 marks
- 4(c)(i) Ethyl levulinate with excess methylmagnesium bromide10 marks
- 4(c)(ii) Reimer–Tiemann reaction of p-cresol: normal and abnormal products10 marks