Q4(c)(i). Ethyl levulinate with excess methylmagnesium bromide
Predict the structure of (X) and (Y) in the following sequence:
[structure] → ((1) Excess MeMgBr, (2) Et₂O) (X)(Y) [structure]
Answer in brief
X = 2,5-dimethylhexane-2,5-diol (from three additions of MeMgBr); Y = the tertiary carbocation formed by loss of water in acid; its ring closure gives 2,2,5,5-tetramethyltetrahydrofuran.
Key points
- MeMgBr adds to C=O (nucleophilic addition) to give a tertiary magnesium alkoxide.
- MeMgBr adds to the ester C=O, the tetrahedral intermediate expels EtO⁻ to give a methyl ketone, which at once takes a second MeMgBr. Overall 3 MeMgBr are used.
- Work-up (H₃O⁺) gives X = 2,5-dimethylhexane-2,5-diol, (CH₃)₂C(OH)CH₂CH₂C(OH)(CH₃)₂.
- In acid one OH is protonated and leaves as water: Y = the tertiary carbocation (CH₃)₂C+CH₂CH₂C(OH)(CH₃)₂ (via the oxonium ion).
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
Introduction. Ethyl levulinate has a ketone and an ester. Excess Grignard reagent adds once to the ketone and twice to the ester (ester → ketone → tertiary alkoxide). Both ends become tertiary alcohols, which close to a cyclic ether in acid.
Reading of the question: step (2) printed as Et₂O is read as the ether solvent followed by aqueous work-up (H₃O⁺); the unlabelled arrows are acid-catalysed steps.
Scheme: Three equivalents of MeMgBr, then an intramolecular SN1 ring closure.
- Ketone: MeMgBr adds to C=O (nucleophilic addition) to give a tertiary magnesium alkoxide.
- Ester: MeMgBr adds to the ester C=O, the tetrahedral intermediate expels EtO⁻ to give a methyl ketone, which at once takes a second MeMgBr. Overall 3 MeMgBr are used.
- Work-up (H₃O⁺) gives X = 2,5-dimethylhexane-2,5-diol, (CH₃)₂C(OH)CH₂CH₂C(OH)(CH₃)₂.
- In acid one OH is protonated and leaves as water: Y = the tertiary carbocation (CH₃)₂C+CH₂CH₂C(OH)(CH₃)₂ (via the oxonium ion).
- The second OH, five atoms away, attacks the cation (5-exo ring closure, intramolecular SN1); loss of H⁺ gives 2,2,5,5-tetramethyltetrahydrofuran.
Conclusion. X = 2,5-dimethylhexane-2,5-diol (from three additions of MeMgBr); Y = the tertiary carbocation formed by loss of water in acid; its ring closure gives 2,2,5,5-tetramethyltetrahydrofuran.
Application. 2,2,5,5-Tetramethyloxolane is a peroxide-resistant ether proposed as a greener solvent in place of toluene; tertiary diols of this kind are also the standard precursors of such hindered ethers.
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All parts of Question 4
- 4(a) Sydnone and imidazole; imidazolium and imidazolide ions15 marks
- 4(b) 'Etard reaction, Clemmensen reduction, Michael addition15 marks
- 4(c)(i) Ethyl levulinate with excess methylmagnesium bromide10 marks
- 4(c)(ii) Reimer–Tiemann reaction of p-cresol: normal and abnormal products10 marks