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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper II covers organic chemistry and spectroscopy.

UPSC Civil Services (Mains), Chemistry optional · 2025 · Paper II

Q6(b). Three numericals

Question

(i) Calculate the frequency of radiation required for a transition of J = 4 to J = 5 in the rotational spectrum of HCl. The rotational constant B = 10.6 cm⁻¹. (5 marks) (ii) The fundamental vibrational frequency of HCl is 2990 cm⁻¹. Calculate the fundamental vibrational frequency of DCl assuming the same bond strength. (5 marks) (iii) The molecular formula of a compound is C₃H₃N. The IR absorption frequencies are 1650 cm⁻¹, 2250 cm⁻¹ and 3100 cm⁻¹. Assign a structure for the compound. (5 marks)

Answer in brief

(i) 106 cm⁻¹, that is 3.18 × 10¹² Hz; (ii) DCl fundamental 2143 cm⁻¹; (iii) acrylonitrile, CH₂=CH–C≡N.

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Coversrotational transitionisotope shiftreduced massIR spectroscopyacrylonitrileHCl DCl