UPSC Combined Geo-Scientist, Mains · 2019 · Mains Paper I
Q1(b). Carbon isotopes and stability
Question
Carbon-14 is radioactive and beta-emitter while carbon-12 is not radioactive. Justify.
Answer in brief
Carbon-14 is neutron rich and undergoes β⁻ decay to stable nitrogen-14; carbon-12 lies in the stable light-nucleus region.
Key points
- ¹²₆C has six protons and six neutrons. For light nuclei a neutron/proton ratio near one is usually favourable; carbon-12 is even–even and stable.
- ¹⁴₆C has eight neutrons and six protons. A neutron converts into a proton, reducing the neutron excess while preserving mass number.
- The decay is ¹⁴₆C → ¹⁴₇N+e⁻+ν̄ₑ. Nitrogen-14 has seven protons and seven neutrons. Decay is possible because the full mass-energy balance is favourable.
The full model answer
As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

CoversCarbon isotopesstabilityNuclear chemistry
All parts of Question 1
- 1(a) Permanganate and iron(II)5 marks
- 1(b) Carbon isotopes and stability5 marks
- 1(c) Diagonal relationship5 marks
- 1(d) Conductivity of phosphoric acid5 marks
- 1(e) Oxidation of Fe(II) and Mn(II)5 marks
- 1(f) Melting points of bromine and iodine chloride5 marks
- 1(g) Small dipole moment of CO5 marks
- 1(h) Acidity of concentrated HF5 marks
- 1(i) Temperature and conductivity5 marks
- 1(j) Diborane with excess ammonia5 marks