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UPSC Combined Geo-Scientist

Chemist

  • 3 descriptive papers
  • 200 marks each
  • 3 h per paper

Mains Paper II covers physical chemistry.

UPSC Combined Geo-Scientist, Mains · 2016 · Mains Paper II

Q1(b). Inclined capillary

Question

A capillary of radius 0.001 cm is inclined at 45° to the liquid surface. The liquid wets the wall, has density 0.85 g cm⁻³ and surface tension 36 dyn cm⁻¹. Calculate the distance along the tube to the meniscus.

Answer in brief

The distance along the capillary is 1.22 m, assuming complete wetting.

Key points

  • Take the contact angle as zero and g=9.81 m s⁻². Convert r=10⁻⁵ m, ρ=850 kg m⁻³ and γ=0.036 N m⁻¹.
  • Balance the upward surface-tension force and the weight of the vertical column: 2π rγcos θ=π r²hρ g. Thus h=2γ/(ρ gr)=0.8635 m.
  • The requested length is l=h/sin 45°=1.221 m. If the contact angle is nonzero, multiply this value by cos θ.

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(b), 2016 Mains Paper II: solution pages 1 and 2
Solution pages 1 and 2 of 19

CoversInclined capillarySurface tension