UPSC Combined Geo-Scientist, Mains · 2018 · Mains Paper II
Q1(k). Heat of spontaneous adsorption
Question
Why is spontaneous adsorption of a gas on a solid at constant temperature and pressure exothermic? Use thermodynamic principles.
Answer in brief
Gas adsorption usually reduces entropy; spontaneity then requires a sufficiently negative enthalpy change.
Key points
- At constant T,p, a spontaneous change has ΔG=ΔH-TΔS<0.
- On adsorption, gas molecules lose much of their translational freedom and become localised at surface sites. For the usual gas-on-solid case, ΔS<0.
- Consequently ΔH<TΔS<0: heat must be released to overcome the unfavourable entropy contribution. Attractive adsorbate–surface interactions provide this energy lowering.
- This argument assumes the usual negative adsorption entropy; coupled solvent release or surface reactions can require a fuller entropy balance.
The full model answer
As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

CoversHeat of spontaneous adsorptionSurface thermodynamics
All parts of Question 1
- 1(a) Equal molecular speeds5 marks
- 1(b) Fugacity under repulsion5 marks
- 1(c) Wetting of glass5 marks
- 1(d) FCC particle count5 marks
- 1(e) Joule–Thomson cooling5 marks
- 1(f) Gibbs and Helmholtz changes5 marks
- 1(g) Equilibrium-constant conventions5 marks
- 1(h) Very dilute hydrochloric acid5 marks
- 1(i) Pressure controlling boiling5 marks
- 1(j) Primary kinetic salt effect5 marks
- 1(k) Heat of spontaneous adsorption5 marks
- 1(l) Conductivity as an intensive property5 marks
- 1(m) Anthracene photodimerization5 marks
- 1(n) Particle-in-a-box eigenvalue5 marks
- 1(o) Second Balmer line5 marks
- 1(p) Normal-mode counts5 marks